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3 years ago

What happens to the buoyant force on an object as it is lowered into water?

1 answer:

8 0

The buoyant force is the upward force or thrust...Simply, consider immersing your hand into a bucket of water. What happens to it? It raises (a little). The raising is due to the buoyant force. Basically it is the upward force/thrust that acts on any object immersed into a fluid. Hence why things float when out in water. Hope this helped!!

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(b) The conductivity of a 0.01 mol dm–3 solution of a monobasic organic acid in water is 5.07 × 10–2 S m–1. If the molar conduct

Zarrin [17]

Explanation:

The given data is as follows.

$\Lambda^{o}_{m}$ (NaCl) = $1.264 \times 10^{-2}$

$\Lambda^{o}_{m}$ (H-O=C-ONO) = $1.046 \times 10^{-2}$

$\Lambda^{o}_{m}$ (HCl) = $4.261 \times 10^{-2}$

Conductivity of monobasic acid is $5.07 \times 10^{-2} S m^{-1}$

Concentration = 0.01 $mol/dm^{3}$

Therefore, molar conductivity ( $\Lambda_{m}$ ) of monobasic acid is calculated as follows.

$\Lambda_{m} = \frac{conductivity}{concentration}$

= $\frac{5.07 \times 10^{-2} S m^{-1}}{0.01 mol/dm^{3}}$

= $\frac{5.07 \times 10^{-2} S m^{-1}}{0.01 mol \times 10^{3}}$

= $5.07 \times 10^{-3} S m^{2} mol^{-1}$

Also, $\Lambda^{o}_{m}$ = $\Lambda^{o}_{m}_{(HCl)} + \Lambda^{o}_{m}_{(H-O=C-ONO)} - \Lambda^{o}_{m}_{(NaCl)}$

= $4.261 \times 10^{-2} + 1.046 \times 10^{-2} - 1.264 \times 10^{-2}$

= $4.043 \times 10^{-2} S m^{2} mol^{-1}$

Relation between degree of dissociation and molar conductivity is as follows.

$\alpha = \frac{\Lambda_{m}}{\Lambda^{o}_{m}}$

= $\frac{5.07 \times 10^{-2} S m^{-1}}{4.043 \times 10^{-2} S m^{2} mol^{-1}}$

= 0.1254

Whereas relation between acid dissociation constant and degree of dissociation is as follows.

K = $\frac{c \times \alpha^{2}}{1 - \alpha}$

Putting the values into the above formula we get the following.

K = $\frac{c \times \alpha^{2}}{1 - \alpha}$

= $\frac{0.01 \times (0.1254)^{2}}{1 - 0.1254}$

= $0.017973 \times 10^{-2}$

= $1.7973 \times 10^{-4}$

Hence, the acid dissociation constant is $1.7973 \times 10^{-4}$ .

Also, relation between $pK_{a}$ and $K_{a}$ is as follows.

$pK_{a} = -log K_{a}$

= $-log (1.7973 \times 10^{-4})$

= 3.7454

Therefore, value of $pK_{a}$ is 3.7454.

3 0

3 years ago

What is the limiting reactant for the following balanced equation when 9 moles of AlF3 are mixed with 12 miles of O2?

tamaranim1 [39]

<h2>Answer: $AlF_{3}$ </h2>

Explanation:

The chemical equation of the reaction that occurs when $AlF_{3}$ reacts with $O_{2}$ is

$4AlF_{3}+3O_{2}$ → $2Al_{2}O_{3}+6F_{2}$

$4$ moles of $AlF_{3}$ requires $3$ moles of $O_{2}$ .

$1$ mole of $AlF_{3}$ requires $\frac{3}{4}$ moles of $O_{2}$ .

Given that we have $9$ moles of $AlF_{3}$ .

$9$ moles of $AlF_{3}$ requires $\frac{3}{4}\times 9=6.75$ moles of $O_{2}$ .

But we have $12$ moles of $O_{2}$ .

So, $AlF_{3}$ will be consumed first.

So, $AlF_{3}$ is the limiting reagent.

3 0

3 years ago

What can you do differently for

drek231 [11]

Answer:

I would say, what helps me is really paying attention in class and asking questions, also making sure you study for upcoming test's and quizzes and completely assingments on time

Explanation:

3 0

3 years ago

The density of tin is 7.31 g/cm? What is the mass of the sample pictured below?

Oduvanchick [21]

Answer:

8.1 g/cm3.

Explanation:

5 0

3 years ago

Why are metals <br> electropositive in nature<br>

Mariana [72]

Answer:

The tendency of metals to lose electrons inorder to get stability is called electropositive nature ofmetals. In general most of the metalslose electrons from their valence shell due to weak force of attraction on the outermost shell.

7 0

3 years ago