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lora16 [44]
3 years ago
15

A sample of a compound contains ​0.300 mol​ ​of carbon​ and ​1.20 mol​ ​of hydrogen​. What is the ​empirical formula of the comp

ound?
Chemistry
1 answer:
Margarita [4]3 years ago
3 0

Answer:

CH4

Explanation:

The number of moles of carbon and hydrogen has been given as follows:

C = ​0.300 mol​ ​

H = ​1.20 mol

Next, we divide each mole value by the smallest (0.300)

C = 0.300 ÷ 0.300 = 1

H = 1.20 ÷ 0.300 = 4

The empirical ratio of Carbon and Hydrogen is 1:4, hence, the empirical formula is CH4

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How many grams of perchloric acid should be dissolved in 8500mL of water to make a solution with pH 3.3
Natalija [7]

Answer:

0.427 g HClO4

Explanation:

[H+]= 10^-3.3 = 5.01 x 10^-4 M

8500 mL=8.5 L

M= mol solute/ L solution

mol solute= M* L solution

mol solute= (5.01 x 10^-4 M * 8.5 L)

mol solute= 4.26 x 10^3 mol HClO4

1 mol HClO4             -> 100. 4 g

4.26 x 10^3 mol HClO4 -> x

x=0.427 g HClO4

3 0
3 years ago
during a rising tide, ocean waves often become larger. if the amplitude of a wave increases by a factor of 1.1, by how much does
Sergio039 [100]

Answer:

1.21 times

Explanation:

The energy of a wave is proportional to the square of the amplitude of the wave.

Mathematically:

E\propto A^2

where

E is the energy of the wave

A is its amplitude

In this problem, the amplitude of the wave increases by a factor of 1.1; it means that the new amplitude can be written as

A'=1.1 A

Therefore, this means that the energy of the wave increases by a factor:

E'\propto A'^2=(1.1 A)^2 = 1.1^2 A^2 =1.21 A^2 = 1.21 E

Therefore, the energy of the wave increases by a factor 1.21.

8 0
4 years ago
Four students drew part of the rock cycle on the board. Which drawing was correct?
Alexeev081 [22]

Answer:the answer is C

Explanation:

I got it right on my test

3 0
3 years ago
A 2.00 L sample of gas at 35C is to be heated at constant pressure until it reaches a volume of 5.25 L. To what Kelvin temperatu
Anastaziya [24]

Answer:

The sample will be heated to 808.5 Kelvin

Explanation:

Step 1: Data given

Volume before heating = 2.00L

Temperature before heating = 35.0°C = 308 K

Volume after heating = 5.25 L

Pressure is constant

Step 2: Calculate temperature

V1 / T1 = V2 /T2

⇒ V1 = the initial volume = 2.00 L

⇒ T1 = the initial temperature = 308 K

⇒ V2 = the final volume = 5.25 L

⇒ T2 = The final temperature = TO BE DETERMINED

2.00L / 308.0 = 5.25L / T2

T2 = 5.25/(2.00/308.0)

T2 = 808.5 K

The sample will be heated to 808.5 Kelvin

7 0
4 years ago
Which of the following is an example of point-source pollution? A. Salt from roads B. Water from a sewage treatment plant C. Fer
ivanzaharov [21]

Answer:

Acid from abandoned mines- D.

7 0
3 years ago
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