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2 years ago

10

Magnetism: So I need help on this question but please explain how you got the answer so I can learn and better provide evidence

:) If you are able to answer this I also am putting a few questions on here for this similar subject for my test and pls explain them all ty!

1 answer:

kramer2 years ago

7 0

Step-by-step explanation:

A) as you can see there is no current flowing in a bar magnet so (incorrect)

B) Lines of magnetic field is going in A-->B direction so it have starting and ending points.(incorrect)

C) Yes whenever a magnetic object is placed near the another magnetic object they either attract or repell so they have a force in a form of push and pull [correct]

D)No because magnetic field lines goes from North--> South so A is the South pole [ incorrect]

E) Yes it will point always towards North pole of the magnet [correct]

F) yes it depends upon the density of field lines[correct]

G)No the near the magnet is it becomes more stronger as compared to magnet kept far.(incorrect)

So option C E F are correct

Hope this helps

Have a great day

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I’ve tried to work this out but I can’t get it figured out. Can someone help me

Bas_tet [7]

G(2) = -4(2) = -8
f(g(2)) = (-8)^2 = 64

answer
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2 years ago

Dvinal [7]

Answer B

Explanation: Y=mx+b
M=slope and b=yintercept

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2 years ago

Help with this one because I do not know how to do perpendicular plz put explanation with steps worth 50!

Yuri [45]

Answer:

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line $2x-3y=12$ is $3x+2y=34$

Step-by-step explanation:

Given:

$2x-3y=12$

To Find:

Equation of line passing through ( 16, -7) and is perpendicular to the line

$2x-3y=12$

Solution:

$2x-3y=12$ ...........Given

$\therefore y=\dfrac{2}{3}\times x-4$

Comparing with,

$y=mx+c$

Where m =slope

We get

$Slope = m1 = \dfrac{2}{3}$

We know that for Perpendicular lines have product slopes = -1.

$m1\times m2=-1$

Substituting m1 we get m2 as

$\dfrac{2}{3}\times m2=-1\\\\m2=-\dfrac{3}{2}$

Therefore the slope of the required line passing through (16 , -7) will have the slope,

$m2=-\dfrac{3}{2}$

Now the equation of line in slope point form given by

$(y-y_{1})=m(x-x_{1})$

Substituting the point (16 , -7) and slope m2 we will get the required equation of the line,

$(y-(-7))=-\dfrac{3}{2}\times (x-16)\\\\2y+14=-3x+48\\3x+2y=34......Equation\ of\ line$

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line $2x-3y=12$ is

$3x+2y=34$

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2 years ago

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Bond [772]

Answer:

HEy, dont every do tht

Step-by-step explanation:

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3 years ago

Read 2 more answers

3x+2y=23<br> 1/2x-4=y<br><br> What should I do for this one...? I dont really understand

Hitman42 [59]

Since you have y alone on one side of the equation......

Use substitution and plug in 1/2x-4 for y in the other equation.

$3x+2(1/2x-4)=23\\$

Distribute

$3x+x-8=23$

Combine like terms

$4x-8=23$

Add 8 to both sides

$4x=31$

Divide by 4

and $x=31/4$

Plug this value in for x

$31/4*1/2-4=y$

Simplify

$31/8-4=y$

Multiply everything by 8 and simplify

$31-32=8y\\-1=8y$

Divide.....

$y=-1/8$

Your answers are:

$y=-1/8\\x=31/4$

8 0

2 years ago