Write an expression that can be used to solve the problem.
1 answer:
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First of all, you have to find the area of both triangles:
Or just 16 because there are 2 of the same triangles.
Now you have to find the area of the 3 rectangles.
The two that are in the front are 4*3 (l*h) or 12*2 (because there are 2 congruent rectangles. The area of those rectangles is 24 square mm.
Now you find the area of the back rectangle:
5.7*3 = 17.1
Finally, you add all the found numbers to figure out the surface area.
17.1 + 16 + 24 = 57.1 square millimeters.
Hope this helped,
Loafly
Or just 16 because there are 2 of the same triangles.
Now you have to find the area of the 3 rectangles.
The two that are in the front are 4*3 (l*h) or 12*2 (because there are 2 congruent rectangles. The area of those rectangles is 24 square mm.
Now you find the area of the back rectangle:
5.7*3 = 17.1
Finally, you add all the found numbers to figure out the surface area.
17.1 + 16 + 24 = 57.1 square millimeters.
Hope this helped,
Loafly
Answer:
Step-by-step explanation:
denotes the set of elements in both A and C, which is
.
denotes the complement of set B, which is the set of all elements that are in the universal set that are not in set B. In this case, this set is