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garri49 [273]
2 years ago
11

Someone please help i think im just over looking it

Mathematics
1 answer:
Nina [5.8K]2 years ago
3 0
Answer: sen = -15; cos= 8

cot is the cotangent which is calculated by dividing cos by sen. So the dominator(15) is sen and the other number is the cos.
Notice that the number is negative which means one of them (sen or cos) is negative. We know that the angule is in the forth quadrant, and that tells us that, in that quadrant, x is a positive number while y is negative.
X is the cos function and Y is the sen. So, if y is negative, so is sen.
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If f(x) = 5x + 4, which of the following is the inverse of (fx)?​
lys-0071 [83]

Answer:

see explanation

Step-by-step explanation:

let y = f(x) and rearrange making x the subject, that is

y = 5x + 4 ( subtract 4 from both sides )

y - 4 = 5x ( divide both sides by 5 )

\frac{y-4}{5} = x

Change y back into terms of x

f^{-1} (x) = \frac{x-4}{5}

3 0
3 years ago
What is the distance between the points (−7, 7) and (−7, 8) ?
Vesnalui [34]

Answer:1

Step-by-step explanation:

5 0
3 years ago
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Find the GCF of 27x^2 and 45x^3y^2
Inga [223]

Step-by-step explanation:

27x² = 3*3*3*x*x

45x³y² = 3*3*5*x*x*x*y*y

Now

GCF = 3 * 3 *x * x = 9x²

6 0
3 years ago
7 = -x+3. Consider the line y = Find the equation of the line that is parallel to this line and passes through the point (-5, 6)
artcher [175]

Answer with explanation:

The equation of line is, y= -x +3

→x+y-3=0---------(1)

⇒Equation of line Parallel to Line , ax +by +c=0 is given by, ax + by +K=0.

Equation of Line Parallel to Line 1 is

  x+y+k=0

The Line passes through , (-5,6).

→ -5+6+k=0

→ k+1=0

→k= -1

So, equation of Line Parallel to line 1 is

x+y-1=0

⇒Equation of line Perpendicular  to Line , ax +by +c=0 is given by, bx - a y +K=0.

Equation of Line Perpendicular to Line 1 is

  x-y+k=0

The Line passes through , (-5,6).

→ -5-6+k=0

→ k-11=0

→k= 11

So, equation of Line Parallel to line 1 is

x-y+11=0

4 0
2 years ago
Find the inverse of y=100-x^2
AnnyKZ [126]

Answer:

The inverse  is ±sqrt(100-x)

Step-by-step explanation:

To find the inverse, exchange x and y

x = 100 -y^2

Solve for y

Subtract 100 from each side

x - 100 = -y^2

Divide by -1

-x +100 = y^2

Take the square root of each side

±sqrt(100-x) = sqrt(y^2)

±sqrt(100-x) =y

The inverse  is ±sqrt(100-x)

5 0
2 years ago
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