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garri49 [273]
3 years ago
11

Someone please help i think im just over looking it

Mathematics
1 answer:
Nina [5.8K]3 years ago
3 0
Answer: sen = -15; cos= 8

cot is the cotangent which is calculated by dividing cos by sen. So the dominator(15) is sen and the other number is the cos.
Notice that the number is negative which means one of them (sen or cos) is negative. We know that the angule is in the forth quadrant, and that tells us that, in that quadrant, x is a positive number while y is negative.
X is the cos function and Y is the sen. So, if y is negative, so is sen.
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The solution for l4  is  mathematically given as

L_{4}=0.5431

<h3>What is the solution for l4?</h3>

&\text { Given } f(x)=a \cos ^{2}(x) \quad\left[\frac{\pi}{8}, \frac{\pi}{2}\right] \text { \& } n=4\\\\&\Delta a=\frac{b-a}{n}=\frac{\pi / 2-\pi / 8}{9}=\frac{3 \pi}{32}\\\\&x_{0}=\pi / 8, x_{1}=\frac{\pi}{8}+\frac{3 \pi}{32}=\frac{7 \pi}{32}\\\\&x_{2}=\frac{5 \pi}{16}, \quad x_{3}=\frac{13 \pi}{32}, x_{4}=\pi / 2\\\\&f\left(x_{0}\right)=f(1 / 8)=0.8535\\

&f\left(x_{1}\right)=f\left(\frac{7 \pi}{32}\right)=0.5975\\\\\&f\left(x_{2}\right)=f\left(\frac{5 \pi}{16}\right)=0.3086\\\\\&f\left(a_{3}\right)=f\left(\frac{13 \pi}{32}\right)=0.0842\\\\\&L_{4}=\sum_{k_{0}^{=0}}^{3} f\left(x_{k}\right) \Delta x\\\\&=\Delta \\\\x\left[f\left(x_{0}\right)+f\left(x_{1}\right)+f\left(x_{2}\right)+f\left(x_{3}\right)\right]\\\\\&=\frac{3 \pi}{32}[0.8535+0.5975+0.3056+0.0842]\\\\&L_{4}=0.5431

Read more about  approximation

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The complete Question is attached below

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2 years ago
The length of a rectangular rug is 4 feet more than the width. If the area of the rug is 252 square feet, find the dimensions of
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Hope this Helps! :)


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3 years ago
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