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zaharov [31]
2 years ago
10

A sample of excited atoms lie 3.314×10−19 J above the ground state. Determine the emission wavelength of these atoms.

Chemistry
1 answer:
BabaBlast [244]2 years ago
8 0

The emission wavelength of the atoms excited above the ground state is 599.8 nm.

<h3>Emission wavelength of the atoms</h3>

The emission wavelength of the atom is determined by using the following formulas as shown below;

E = hf

E = hc/λ

where;

  • E is the energy of the atom
  • h is Planck's constant
  • c is speed of light
  • λ is the emission wavelength

λ = hc/E

λ = (6.626 x 10⁻³⁴ x 3 x 10⁸) / (3.314 x 10⁻¹⁹)

λ = 5.998 x 10⁻⁷ m

λ = 599.8 x 10⁻⁹ m

λ = 599.8 nm

Thus, the emission wavelength of the atoms is 599.8 nm.

Learn more about wavelength here: brainly.com/question/10728818

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When copper metal is added to nitric acid, the following reaction takes place
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The volume of NO₂ gas collected over water at 25.0 °C is 1.68 Liters.

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