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3 years ago

How many grams of carbon dioxide are created from the complete

Chemistry

1 answer:

ololo11 [35]3 years ago

7 0

Answer:

167.2 g

Explanation:

Known

VC4H10 = 21.3

T = 0.00 C (convert to Kelvin: 273 K)

P = 1.00 atm

Unknown

m = ?g

1. Write the balanced chemical equation

1 C4H10 + 1O2 -----> 4 CO2 + 5 H2O

2. Find the volume ratio of Carbon Dioxide to Butane

1 C4H10 4 CO2 = 4 volumes CO2 / 1 volume C4H10

3. Multiply by the known volume of n (butane)

21.3 L C4H10 x 4 volumes CO2 / 1 volume C4H10 = 85.2 L C4H10

4. Use ideal gas law

PV = nRT solve for n ----> n = PV/RT

n= (1.00 atm) (85.2 L) / (0.0821 L atm/mol K) (273) = 3.80 mol CO2

5. Find molar mass of CO2

1 C x 12 + 2 O x 16 = 44.00

6. Multiply the ideal gas law solution (3.80) by molar mass CO2 (44.00)

3.80 mol CO2 x 44.00 g CO2

= 167.2 g CO2

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One cup of fresh orange juice contains 139 mg of ascorbic acid (vitamin c, c6h8o6) given that one cup = 264.8 ml calculate the m

SVEN [57.7K]

The answer to this question would be: 3 molar
A molar unit will be equal to moles of solute per 1 liter of solvent. In this question, you are given the volume of the solution (264.8ml) and the weight of the molecule(139mg). Since the unit is moles not mg, then you need to convert the molecule into moles. To do that you need to know the ascorbic acid molecular weight which was: 6*12 + 8*1 + 6 *16 =176mg/moles.

molecule in moles= 139mg/ (176 mg/moles)= 0.79 moles

Then the molarity of the juice should be: 0.79 moles/ (1000ml/264ml)= 2.991 M= 3 M

4 0

4 years ago

Look at the image shown. What does this image represent?

JulijaS [17]

Answer:

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Explanation:

8 0

3 years ago

Calculate the amount of heat released in the combustion of 10.5 grams of Al with 3 grams of O2 to form Al2O3(s) at 25°C and 1 at

ElenaW [278]

Answer : The amount of heat released in the combustion is, 209.5 kJ

Explanation :

First we have to calculate the moles of Al and $O_2$ .

$\text{ Moles of }Al=\frac{\text{ Mass of }Al}{\text{ Molar mass of }Al}=\frac{10.5g}{27g/mole}=0.389moles$

$\text{ Moles of }O_2=\frac{\text{ Mass of }O_2}{\text{ Molar mass of }O_2}=\frac{3g}{32g/mole}=0.188moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction will be:

$4Al+3O_2\rightarrow 2Al_2O_3$

From the balanced reaction we conclude that

As, 3 mole of $O_2$ react with 4 mole of $Al$

So, 0.188 moles of $O_2$ react with $\frac{4}{3}\times 0.188=0.251$ moles of $Al$

From this we conclude that, $Al$ is an excess reagent because the given moles are greater than the required moles and $O_2$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $Al_2O_3$

From the reaction, we conclude that

As, 3 mole of $O_2$ react to give 2 mole of $Al_2O_3$

So, 0.188 moles of $O_2$ react to give $\frac{2}{3}\times 0.188=0.125$ moles of $Al_2O_3$

Now we have to calculate the amount of heat released in the combustion.

As, 1 mole of $Al_2O_3$ releases amount of heat = 1676 kJ

So, 0.125 mole of $Al_2O_3$ releases amount of heat = $0.125\times 1676kJ=209.5kJ$

Thus, the amount of heat released in the combustion is, 209.5 kJ

4 0

3 years ago

Consider the following reaction at equilibrium: C(s)+H2O(g)⇌CO(g)+H2(g) Predict whether the reaction will shift left, shift righ

vazorg [7]

'Answer:

a) C is added to the reaction mixture. "shift right"

b) H₂O is condensed and removed from the reaction mixture. "shift left"

c) CO is added to the reaction mixture. "shift left"

d) H₂ is removed from the reaction mixture. "shift right"

Explanation:

Le Châtelier's principle states that when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium.

a) C is added to the reaction mixture:

Adding C(s) will increase the concentration of the reactants side, so the reaction will be shifted to the right side to suppress the increase in the concentration of C by addition.

So, the reaction shift right.

b) H₂O is condensed and removed from the reaction mixture:

Removing H₂O will decrease the concentration of the reactants side, so the reaction will be shifted to the left side to suppress the decrease in the concentration of H₂O by removal.

So, the reaction shift left.

c) CO is added to the reaction mixture:

Adding CO will increase the concentration of the products side, so the reaction will be shifted to the left side to suppress the increase in the concentration of CO by addition.

So, the reaction shift left.

d) H₂ is removed from the reaction mixture:

Removing H₂ will decrease the concentration of the products side, so the reaction will be shifted to the right side to suppress the increase in the concentration of H₂ by removal.

So, the reaction shift right.

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3 years ago

Which statement explains why carbon dioxide (CO2) is a gas at room temperature? A. There are constant interactions between the C

Nezavi [6.7K]

Answer:

B) There are weak interactions between the CO2 molecules.

Explanation:

Carbon dioxide is composed of one carbon atom that is structured between two atoms of oxygen, they are bonded with double bond and the CO2 is symmetrical because of the arrangement of the bond between them.It is less electronegative than Oxgen, this gives Oxgen the ability to attract the electron to themselves, and there is no intermolecular existing within carbon dioxide other bands waal forces.Compounds that are gases under the condition of room temperatures, and pressure usually have have small molecules. and their molecules is usually have van der Waals forces acting between them and theses forces are weak.This allows carbon dioxide molecules to be able to move freely as a gas.

6 0

4 years ago