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Trava [24]
2 years ago
15

WILL MARK BRAINLIEST!!!

Mathematics
1 answer:
MArishka [77]2 years ago
8 0

Answer is From all those aforementioned, the true statement is: Thanh’s grade is 2.5 standard deviations below the mean of the test grades.

explanation

The z scores are standard deviations. If, for example, a tool returns a z score of +2.5, it means that the result is a standard deviation of 2.5. Very high or very low (negative) z scores associated

with very low p values are at the ends of the normal distribution.

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100-(2 8/5+1 3/8)×(3.05-0.8
Leya [2.2K]
<span>88.80625 is the answer because I used a calculator.</span>
5 0
3 years ago
Given △XPS≅△DNF, find the values of x and y.
White raven [17]

Answer:

x = 3

y = 15

Step-by-step explanation:

If △XPS ≅△DNF, their corresponding sides would be congruent. This implies that:

XP ≅ DN

PS ≅ NF

XS ≅ DF

Given that:

XP = 4y - 3

DN = 57

NF = 51

XS = 17x + 3

DF = 54

Therefore:

XP = DN

4y - 3 = 57 (Substitution)

Add 3 to both sides

4y = 57 + 3

4y = 60

Divide both sides by 4

y = 60/4

y = 15

Also,

XS = DF

17x + 3 = 54 (substitution)

Subtract 3 from each side

17x = 54 - 3

17x = 51

Divide both sides by 17

x = 51/17

x = 3

4 0
3 years ago
Anthony bought an 8-foot board. He cut off 3/4 of the board to build a shelf and gave 1/3 of the rest to his brother for an art
AleksAgata [21]
I’m pretty sure the answer is 8 inches, mark as brainleist pls :)
6 0
3 years ago
If f(x)=2x²+5√(x-2) , complete the following statement: f(3)=___
aliya0001 [1]
F(x)=2x²+5√(x-2)

f(3)=2(3)²+5√(3-2)
= 2 (9) + 5√1
= 18 + 5
= 23.
4 0
3 years ago
Determine whether or not the vector field is conservative. if it is conservative, find a function f such that f = ∇f. (if the ve
Akimi4 [234]
A three-dimensional vector field is conservative if it is also irrotational, i.e. its curl is \mathbf 0. We have

\nabla\times\mathbf f(x,y,z)=-2e^{-x}\,\mathbf k

so this vector field is not conservative.

- - -

Another way of determining the same result: We want to find a scalar function f(x,y,z) such that its gradient is equal to the given vector field, \mathbf f(x,y,z):

\nabla f(x,y,z)=\mathbf f(x,y,z)

For this to happen, we need to satisfy

\begin{cases}f_x=ye^{-x}\\f_y=e^{-x}\\f_z=2z\end{cases}

From the first equation, integrating with respect to x yields

f_x=ye^{-x}\implies f(x,y,z)=-ye^{-x}+g(y,z)

Note that g *must* be a function of y,z only.

Now differentiate with respect to y and we have

f_y=-e^{-x}+g_y=e^{-x}\implies g_y=2e^{-x}\implies g(y,z)=2ye^{-x}+\cdots

but this contradicts the assumption that g(y,z) is independent of x. So, the scalar potential function does not exist, and therefore the vector field is not conservative.
8 0
3 years ago
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