Using the binomial distribution, it is found that the mean of X is of 12, with a standard deviation of 3.36.
For each chip, there are only two possible outcomes, either it is defective, or it is not. The probability of a chip being defective is independent of any other chip, hence, the binomial distribution is used to solve this question.
Binomial probability distribution
Probability of exactly <u>x successes on n repeated trials, with p probability.</u>
The mean of the binomial distribution is:
The standard deviation of the binomial distribution is:
In this problem:
- Six percent of computer chips produced by Cheapo Chips are defective, hence
.
- Each month a random sample of 200 chips manufactured that month are taken, hence

Then:


The mean of X is of 12, with a standard deviation of 3.36.
A similar problem is given at brainly.com/question/12473640
300,000 / 4,000 = 75
so the weight of the blue whale is 75 times bigger then the weight of the shark
Answer:
1 hour
Step-by-step explanation:
The number of presale tickets sold is 271
<em><u>Solution:</u></em>
Let "p" be the number of presale tickets sold
Let "g" be the number of tickets sold at gate
<em><u>Given that, total of 800 Pre-sale tickets and tickets at the gate were sold</u></em>
Therefore,
Presale tickets + tickets sold at gate = 800
p + g = 800 ------ eqn 1
<em><u>Given that, number of tickets sold at the gate was thirteen less than twice the number of pre-sale tickets</u></em>
Therefore,
Number of tickets sold at gate = twice the number of pre-sale tickets - 13
g = 2p - 13 ------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
Substitute eqn 2 in eqn 1
p + 2p - 13 = 800
3p -13 = 800
3p = 800 + 13
3p = 813
p = 271
Thus 271 presale tickets were sold