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galina1969 [7]
2 years ago
7

Objects 1 and 2

Physics
1 answer:
sattari [20]2 years ago
3 0

Answer:

12 units

Explanation:

Original F = C q1q2/r^2    now change the parameters

  New F = C  1/3 q1  2 q2  / (2r)^2

              =  2/12  C q1q2/r^2    <=======the new force is 1/6 of original

1/6 * 72 = 12 units  

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Which two staments explain how a cell's parts help it get nutrients
Goryan [66]

Answer:

I think it's A and D.

6 0
3 years ago
A 1400.0 kg car crests a 3200.0 m pass in the mountains and briefly comes to rest. The car descends 1000 m before climbing and c
rjkz [21]

Answer:

a) v = 88.54 m/s

b) vf = 26.4 m/s

Explanation:

Given that;

m = 1400.0 kg

a)

by using the energy conservation

loss in potential energy is equal to gain in kinetic energy

mg × ( 3200-2800) = 1/2 ×m×v²

so

1400 × 9.8 × 400 = 0.5 × 1400 × v²

5488000 = 700v²

v² = 5488000 / 700

v² = 7840

v = √7840

v = 88.54 m/s

b)

Work done by all forces is equal to change in KE

W_gravity + W_non - conservative = 1/2×m×(vf² - vi²)

we substitute

1400 × 9.8 × ( 3200-2800) - (5 × 10⁶) = 1/2 × 1400 × (vf²  -0 )

488000 = 700 vf²

vf² = 488000 / 700

vf² = 697.1428

vf = √697.1428

vf = 26.4 m/s

4 0
4 years ago
How to do this, i'm completely lost
vaieri [72.5K]
There are two torques t1 and t2 on the beam due to the weights, one torque t3 due to the weight of the beam, and one torque t4 due to the string.

You need to figure out t4 to know the tension in the string.

Since the whole thing is not moving t1 + t2 + t3 = t4.

torque t = r * F * sinФ = distance from axis of rotation * force * sin (∡ between r and F)

t1 =3.2 * 44g 
t2 = 7 * 49g 
t3 = 3.5 * 24g 

t4 = t1 + t2 + t3 = 5570,118

The t4 also is given by:

t4 = r * T * sin Ф

r = 7
Ф = 32°
T: tension in the string

T = t4 / (r * sinФ)

T = t4 / (7 * sin(32°)) 

T = 1501,6 N

8 0
4 years ago
What are fossil fuels composed of? 1.Carbon 2.Nitrogen 3.Oxygen
Monica [59]

Answer:

fossil fuels are composed of Carbon.

5 0
3 years ago
Read 2 more answers
A car going around a curve with a radius of 15m experiences a centripetal acceleration of 2.5 m/s2. How fast is the car going?
prisoha [69]

Answer:

Explanation:

The formula for centripetal acceleration is

a_c=\frac{v^2}{r} . Filling in:

2.5=\frac{v^2}{15} and

v=\sqrt{2.5(15)} so

v = 6.1 m/s

8 0
3 years ago
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