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grin007 [14]
3 years ago
5

How do you sound waves reach our ears?

Physics
1 answer:
iren2701 [21]3 years ago
5 0

Answer:

Sound waves enter the outer ear and travel through a narrow passageway called the ear canal, which leads to the eardrum. The eardrum vibrates from the incoming sound waves and sends these vibrations to three tiny bones in the middle ear. These bones are called the malleus, incus, and stapes.

Explanation:

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You are driving a car with an automatic transmission; the shifter is mounted on the steering column. When you press down on the
castortr0y [4]

Answer:

From the narrative in the question, there seem to have been a break failure and the ordered step of response to this problem is to

1) Put on the hazard light to inform other road users of a problem or potential fault with your car and so they should continue their journey with caution.

2) Avoid pressing on the acceleration pedal as this might cause the car to gradually slow down due to friction and gravity

3)Try navigate the car to the service lane. This is the less busy lane where cars are sometimes parked briefly.

4) Continuously pump the breaks to try stop the car. Continuously pumping the breaks might just help you build enough pressure to stop the car because often time, there are some pressure left in the break.

5) At this point, the speed of the car should be relatively slow. So at this point, you could try apply the emergency hand break. Do not pull the emergency hand breaks if the car is on high speed. Doing this may cause the car to skid off the road.

8 0
3 years ago
What is the purpose of each of the components (each shown with leader and line) of the circuit shown is the diagram?
NemiM [27]

The wires is what is needed to put together the whole thing, kinda like glue when you're gluing a piece of paper on it.

Anyways, the battery is the main source and main energy per say.

That energy that comes from the battery, thanks to the wires, it can transfer that said energy to both the switch and light bulb.

And as you flick the switch, it depends of how you put it together, there's two options, turning the light bulb on or turning it off.

Though it doesn't mean that since the light bulb is connected to the battery makes the bulb turn on no matter what since the switch can cancel the main source's energy.

- Ouma :>

5 0
3 years ago
In a region of space where gravitational forces can be neglected, a sphere is accelerated by a uniform light beam of intensity 8
BlackZzzverrR [31]

Answer:

The correct answer is B

Explanation:

To calculate the acceleration we must use Newton's second law

      F = m a

      a = F / m

To calculate the force we use the defined pressure and the radiation pressure for an absorbent surface

       P = I / c        absorbent surface

       P = F / A

       F / A = I / c

       F = I A / c

The area of ​​area of ​​a circle is

      A = π r²

We replace

     F = I π r² / c

Let's calculate

     F = 8.0 10⁻³ π (1.0 10⁻⁶)²/3 10⁸

     F = 8.375 10⁻²³ N

Density is

      ρ = m / V

      m = ρ V

      m = ρ (4/3 π r³)

      m = 4500 (4/3 π (1 10⁻⁶)³)

      m = 1,885 10⁻¹⁴ kg

Let's calculate the acceleration

     a = 8.375 10⁻²³ / 1.885 10⁻¹⁴

     a = 4.44 10⁻⁹ m/s²               absorbent surface

The correct answer is B

4 0
3 years ago
. A 2.0-kg block is on a perfectly smooth ramp that makes an angle of 30° with the horizontal. (a) What is the block’s accelerat
AfilCa [17]

Answer:

a) a = 4.9 m / s²,  N = 16.97 N   and b)   F = 9.8 N

Explanation:

a) For this exercise we will use Newton's second law, we write a reference system with the x axis parallel to the plane, see attached, in this system the only force we have to break down is weight, let's use trigonometry

        sin 30 = Wx / W

        cos 30 = Wy / W

        Wx = W sin30

        Wy = W cos 30

Let's write the equations on each axis

X axis

        Wx = ma

Y Axis  

       N- Wy = 0

       N = Wy = mg cos 30

       N = 2.0 9.8 cos 30

       N = 16.97 N

We calculate the acceleration

       a = Wx / m

       a = mg sin 30 / m

       a = g sin 30

       a =9.8 sin 30

       a = 4.9 m / s²

b) For the block to move with constant speed, the acceleration must be zero, so the force applied must be equal to the weight component

      F -Wx = 0

      F = Wx

      F = m g sin 30

      F = 2.0 9.8 sin 30

      F = 9.8 N

5 0
3 years ago
If a ball is tossed straight up into the air, at what position is its potential energy the greatest?
krok68 [10]
A. when it reaches the top of its flight

potential energy increases as the height of the object does, and the highest point of a ball's flight is when it reaches the top. 
4 0
3 years ago
Read 2 more answers
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