Answer:
I will do A for U
I have 5 apples then got 18 more, so how many apples do I now Have?
Step-by-step explanation:
We can solve this problem using the binomial distribution. A binomial distribution<span> can be thought of as a success or failure outcome in an experiment or survey that is repeated multiple times.
</span>Probability function of binomial distribution has the following form:

p represents the probability of each choice we want. k is the number of choices we want and n is the total number of choices.
In our case p=0.85, k=5 and n=6.
We can now calculate the answer:

The probability is 39%.
.
Answer:
x = 90°
Step-by-step explanation:
The diagonals of the kite AC and BD are perpendicular to each other
Hence x = 90°
Answer:
uhh the slope is 2/3 but the y-intercepy is -2
Step-by-step explanation:
Let
denote the <em>k</em>th term of the sequence. Then

where <em>d</em> is the common difference between consecutive terms in the sequence and <em>a</em>₁ is the first term.
The sum of the first <em>n</em> terms is

From the formula for
, we get




So we have
, and
so that
.
Then the <em>n</em>th term in the sequence is
