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2 years ago

What values of a and b would make the equation shown below have infinitely many solutions?

Mathematics

1 answer:

Leokris [45]2 years ago

5 0

Answer:

a=-3

b=6

Step-by-step explanation:

equation 1: ax+6

equation 2: -3x+b

get the -3 from equation 2 and plug it into equation 1

get the 6 from equation 1 and plug it into equation 2

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Travelers who fail to cancel their hotel reservations when they have no intention of showing up are commonly referred to as no-s

notsponge [240]

Answer:

a) 0.0523 = 5.23% probability that at least two of the four selected will turn to be no-shows.

b) 0 is the most likely value for X.

Step-by-step explanation:

For each traveler who made a reservation, there are only two possible outcomes. Either they show up, or they do not. The probability of a traveler showing up is independent of other travelers. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

No-show rate of 10%.

This means that $p = 0.1$

Four travelers who have made hotel reservations in this study.

This means that $n = 4$

a) What is the probability that at least two of the four selected will turn to be no-shows?

This is $P(X \geq 2) = P(X = 2) + P(X = 3) + P(X = 4)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{4,2}.(0.1)^{2}.(0.9)^{2} = 0.0486$

$P(X = 3) = C_{4,3}.(0.1)^{3}.(0.9)^{1} = 0.0036$

$P(X = 4) = C_{4,4}.(0.1)^{4}.(0.9)^{0} = 0.0001$

$P(X \geq 2) = P(X = 2) + P(X = 3) + P(X = 4) = 0.0486 + 0.0036 + 0.0001 = 0.0523$

0.0523 = 5.23% probability that at least two of the four selected will turn to be no-shows.

b) What is the most likely value for X?

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{4,0}.(0.1)^{0}.(0.9)^{4} = 0.6561$

$P(X = 1) = C_{4,1}.(0.1)^{1}.(0.9)^{3} = 0.2916$

$P(X = 2) = C_{4,2}.(0.1)^{2}.(0.9)^{2} = 0.0486$

$P(X = 3) = C_{4,3}.(0.1)^{3}.(0.9)^{1} = 0.0036$

$P(X = 4) = C_{4,4}.(0.1)^{4}.(0.9)^{0} = 0.0001$

X = 0 has the highest probability, which means that 0 is the most likely value for X.

7 0

3 years ago

The formula for the resistance, R, of a conductor with voltage, V, and current , I , is R= V/I. Solve for V.

borishaifa [10]

Answer:

T+V/I

Step-by-step explanation:

multiply both sides by I to get rid of fractions ti=V

7 0

3 years ago

Read 2 more answers

PLZ HELP PLZ PLZ PLZ

Temka [501]

Answer:

The top option is false.

Step-by-step explanation:

Both segments have a rate of change [slope] of ⅔. It just that their ratios have unique qualities:

$\frac{2}{3} = \frac{4}{6}$

Greatest Common Factor: 2

___ ___

BC is at a 4⁄6 slope, and AB is at a ⅔ slope. Although their quantities are unique, they have the exact same value.

I am joyous to assist you anytime.

3 0

3 years ago

Given P(A) = 0.36, P(B) = 0.2 and P(ANB) = 0.122, find the value of P(AUB), rounding to the nearest thousandth, if necessary.

aliya0001 [1]

Answer:

The value of P(AUB) = 0.438

Step-by-step explanation:

Given:

P(A) = 0.36

P(B) = 0.2

P(A∩B) = 0.122

Find:

The value of P(AUB)

Computation:

P(AUB) = P(A) + P(B) - P(A∩B)

The value of P(AUB) = 0.36 + 0.2 - 0.122

The value of P(AUB) = 0.56 - 0.122

The value of P(AUB) = 0.438

7 0

3 years ago

A car is 160 inches lorrg.

Andreyy89

The truck is 171.2%. if you calculate the percentage of 160 and add them together, you will get 171.2

7 0

2 years ago