An airplane can seat up to 175 passengers. The airline has already sold 87 tickets for a flight on the airplane. Which
1 answer:
The inequality is solved, and then, the graph is given at the end of this question.
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- 87 tickets have already been sold.
- x can still be sold.
- In total, the number of tickets sold is 87 + x.
- The airplane can seat 175 passengers, thus, the total can be at most 175, that is:
- The solution is given on a graph at the end of this answer.
A similar problem is given at brainly.com/question/24132092
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Answer:
if repetition is allowed,
if repetition is not allowed.
Step-by-step explanation:
For the first case, we have a choice of 26 letters <em>each step of the way. </em>For each of the 26 letters we can pick for the first slot, we can pick 26 for the second, and for each of <em>those</em> 26, we can pick between 26 again for our third slot, and well, you get the idea. Each step, we're multiplying the number of possible passwords by 26, so for a four-letter password, that comes out to 26 × 26 × 26 × 26 = possible passwords.
If repetition is <em>not </em>allowed, we're slowly going to deplete our supply of letters. We still get 26 to choose from for the first letter, but once we've picked it, we only have 25 for the second. Once we pick the second, we only have 24 for the third, and so on for the fourth. This gives us instead a pretty generous choice of 26 × 25 × 24 × 23 passwords.