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f′(x)=2∗(8x(2−1))+1∗11x(1−1)
which is
f′(x)=16x+11
then let
x = 7 gives us
f′(7)=123
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Oh no my parrot is missing
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Answer:
A) 5x+12 = -12x-12
D) 5x+12 = -5x-12
Step-by-step explanation:
If you subtract the right side expression from both sides, you will get an equation with something equal to zero. If the 'something' has a variable in it, there is exactly one solution.
A: (5x+12) -(-12x-12) = 17x+24 = 0 . . . one solution
B: (5x+12) -(5x-5) = 17 = 0 . . . . no solutions
C: (5x+12)-(5x+12) = 0 = 0 . . . . infinite solutions
D: (5x+12) -(-5x-12) = 10x +24 = 0 . . . one solution