Firstly, use the distributive property of multiplication (A(B + C) = A×B + A×C) on -2(q - 5) and -3(q + 1): 
Next, apply the addition property of equality (whatever you add to one side you have to add the same quantity to the other), and add 3q on both sides: 
Lastly, apply the subtraction property of equality (whatever you subtract on one side you have to subtract the same amount on the other side), and subtract 10 on both sides. <u>Your final answer will be
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4n² - 15n + 14<span> is always the product of two numbers, for it to be prime number, one of these factors must be either 1 or -1.
Case n - 2 = 1
That would be n = 3
Then </span>4n² - 15n + 14<span> = 5 , which is prime.
Case n - 2 = -1
That would be n = 1
Then </span>4n<span>² - 15n + 14 = 3, which is also prime.
Case 4n - 7 = 1
That would be n = 2 and that makes other factor (n-2) zero so it's not prime
Case 4n-7 = -1
That would be n = 3/2 which is not integer, so </span>4n<span>² - 15n + 14 will not be interger.
For any other n values, </span>4n<span>² - 15n + 14 will be composite number since it is product of two factors.
Therefore we are left with n = 1 and n = 3; only two values of n.</span>
Answer:
B
Step-by-step explanation:
Answer:
see below
Step-by-step explanation:
The tangent function has been shifted upward by 2 units, but there has been no horizontal scaling. Any horizontal offset must be equal to some number of whole periods.
Choices A and B show tan( )+2, the correct vertical offset. However, choice A has a horizontal scale factor of 2. The correct choice is B, which has no horizontal scaling (the coefficient of x is 1) and a horizontal offset of π, one full period.
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<em>Comment on horizontal scaling</em>
Horizontal scaling is different from vertical scaling in that using k·x in place of x <em>compresses</em> the graph horizontally by a factor of k. On the other hand, using k·f(x) in place of f(x) <em>expands</em> the graph vertically by a factor of k.