A 1,500-kilogram car travelling at 10 meters per second (about 22 mph) strikes a parked car on the side of the road. If the car

Question

3 years ago

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comes to a stop in half of a second, what force is exerted on the parked car by the moving car?

1 answer:

Alona [7] · Answer 1 · 2022-12-31T09:56:52+03:00

The force exerted on the parked car by the moving car is –30000 N

To solve this question, we'll begin by calculating the deceleration of the moving car. This can be obtained as follow:

Initial velocity (u) = 10 m/s

Final velocity (v) = 0 m/s

Time (t) = 0.5 s

<h3>Deceleration (a) =?</h3>

$a = \frac{v - u}{t} \\\\ a = \frac{0 - 10}{0.5}\\\\a = \frac{- 10}{0.5}$

Finally, we shall determine the force exerted by the moving car on the parked car. This can be obtained as follow:

Mass of moving car (m) = 1500 Kg

Acceleration (a) = - 20 m/s

<h3>Force (F) =.?</h3>

F = ma

F = 1500 × (-20)

NOTE: The negative sign indicate force is in opposite direction to the parked car.

Therefore, the force exerted on the parked car by the moving car is –30000 N