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lesantik [10]
3 years ago
15

Put the following orbitals in the correct order based on the Aufbau principle: 1s,2s,3s,3p,4s,2p,3d

Chemistry
1 answer:
lord [1]3 years ago
4 0
1 + 2 = 10 jdbq cc, sno aswddwdn i g g e r

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Explanation:

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Which principal energy level can hold a maximum of 18 electrons?
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What is a resonance dot structure? How do you know if you have resonance?
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3 years ago
Calculate ΔHo for the following reaction ussing the given bond dissociation energiesCH4(g) + 2O2(g) --> CO2(g) + 2H2O(g)BOND
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Answer:

The ΔH° for the following reaction is -794 kJ, hence exothermic reaction,

Explanation:

CH_4(g) + 2O_2(g)\rightarrow CO_2(g) + 2H_2O(g) ,ΔH° = ?

We are given with:

\Delta H_{O-O}=142 kJ/mol

\Delta H_{O=O}=498 kJ/mol

\Delta H_{H-O}=459 kJ/mol

\Delta H_{C-H}=411 kJ/mol

\Delta H_{C-O}=358 kJ/mol

\Delta H_{C=O}=799 kJ/mol

ΔH° =  

(Energies required to break bonds on reactant side) - (Energies released on formation of bonds on product side)

\Delta H^o=(1 mol\times 4\times \Delta H_{C-H}+2 mol\times 1\times \Delta H_{O=O})-(1 mol\times 2\times \Delta H_{C=O}+2 mol\times 2\times\Delta H_{H-O})

\Delta H^o=(1 mol\times 4\times 411 kJ/mol+2 mol\times 1\times 498 kJ/mol)-(1 mol\times 2\times 799 kJ/mol+2 mol\times 2\times 459 kJ/mol)

\Delta H^o=-794kJ

\Delta H^o>0 endothermic reaction

\Delta H^o exothermic reaction

The ΔH° for the following reaction is -794 kJ, hence exothermic reaction,

4 0
4 years ago
PLSSS HELP ANYONE ASAP!
algol [13]
B I hope it’s right I don’t really help a lot but yeah lol
7 0
3 years ago
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