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Grace [21]
3 years ago
15

Write 0.006 in exponential form​

Chemistry
1 answer:
Solnce55 [7]3 years ago
7 0

\huge\pink{Answer}

0.0006 in scientific notation is 6 × 10-4

<h2>Step by step Explanation:</h2>

All numbers in scientific notation or standard form are written in the form

m × 10n, where m is a number between 1 and 10 ( 1 ≤ |m| < 10 ) and the exponent n is a positive or negative integer.

To convert 0.0006 into scientific notation, follow these steps:

Move the decimal 4 times to right in the number so that the resulting number, m = 6, is greater than or equal to 1 but less than 10

Since we moved the decimal to the right the exponent n is negative

n = -4

Write in the scientific notation form m × 10n

= 6 × 10-4

Therefore,

6 × 10-4 is the scientific notation form of 0.0006 number and 6e-4 is the scientific e-notation form for 0.0006

<h2>HOPE IT HELPS ☺️</h2>
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2-phosphoglycerate(2PG) is converted to phosphoenolpyruvate (PEP) by the enzyme enolase. The standard free energy change(deltaGo
pogonyaev

Answer:

The correct option is: (D) -2.4 kJ/mol

Explanation:

<u>Chemical reaction involved</u>: 2PG ↔ PEP

Given: The standard Gibb's free energy change: ΔG° = +1.7 kJ/mol

Temperature: T = 37° C = 37 + 273.15 = 310.15 K    (∵ 0°C = 273.15K)

Gas constant: R = 8.314 J/(K·mol) = 8.314 × 10⁻³ kJ/(K·mol)     (∵ 1 kJ = 1000 J)

Reactant concentration: 2PG = 0.5 mM

Product concentration: PEP = 0.1 mM

Reaction quotient: Q_{r} =\frac{\left [ PEP \right ]}{\left [ 2PG \right ]} = \frac{0.1 mM}{0.5 mM} = 0.2

<u>To find out the Gibb's free energy change at 37° C (310.15 K), we use the equation:</u>

\Delta G = \Delta G^{\circ } + 2.303 R T log Q_{r}

\Delta G = 1.7 kJ/mol + [2.303 \times (8.314 \times 10^{-3} kJ/(K.mol))\times (310.15 K)] log (0.2)

\Delta G = 1.7 + [5.938] \times (-0.699) = 1.7 - 4.15 = (-2.45 kJ/mol)

<u>Therefore, the Gibb's free energy change at 37° C (310.15 K): </u><u>ΔG = (-2.45 kJ/mol)</u>

4 0
3 years ago
Science 6th grade please help me :)
Gnom [1K]
I’m pretty sure the answer is D :)
6 0
3 years ago
Read 2 more answers
Given the balanced ionic equation representing the reaction in an operating voltaic cell: zn(s) + cu2+(aq) → zn2+(aq) + cu(s) th
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Answer: from the Zn anode to the Cu cathode


Justification:


1) The reaction given is: Zn(s) + Cu₂⁺ (aq) -> Zn²⁺ (aq) +Cu(s)


2) From that, you can see the Zn(s) is losing electrons, since it is being oxidized (from 0 to 2⁺), while Cu²⁺, is gaining electrons, since it is being reduced (from 2⁺ to 0).


3) Then, you can already tell that electrons go from Zn to Cu.


4) The plate where oxidation occurs is called anode, and the plate where reduction occus is called cathode.


So you get that the electrons flow from the anode (Zn) to the cathode (Cu).


Always oxidation occurs at the anode, and reduction occurs at the cathode.

3 0
3 years ago
Acetic acid is the active ingredient in vinegar. In a solution of acetic acid the following equilibrium is established. HC2H3O2(
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Answer:

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Explanation:

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Compound-
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Molecule- a pure substance that cannot be broken down
Salt- A Ionic Compound Formed From The Reaction Of An Acid And Base .
7 0
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