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krok68 [10]
3 years ago
13

a gas has a pressure of 0.410 atm and a volume of 32L. At what pressure would the volume of the gas change to 28L?

Chemistry
1 answer:
densk [106]3 years ago
8 0

Answer:

The new pressure is 0,469 atm

Explanation:

We apply Boyle Mariotte's Law: for a given mass of gas at constant temperature, its pressure and volume vary inversely proportionally (the higher the pressure, the lower the volume and vice versa):

P1 x V1 = P2 xV2               We solve P2:

P2 = (P1 x V1)/V2

P2= (0,410 atm x 32 L) / 28 L

<em>P2= 0,469 atm</em>

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For the following reaction, 4.31 grams of iron are mixed with excess oxygen gas . The reaction yields 5.17 grams of iron(II) oxi
natka813 [3]

<u>Answer:</u> The theoretical yield of iron (II) oxide is 5.53g and percent yield of the reaction is 93.49 %

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}       ....(1)

  • <u>For Iron:</u>

Given mass of iron = 4.31 g

Molar mass of iron = 53.85 g/mol

Putting values in above equation, we get:  

\text{Moles of iron}=\frac{4.31g}{53.85g/mol}=0.0771mol

For the given chemical reaction:

2Fe(s)+O_2(g)\rightarrow 2FeO(s)

By Stoichiometry of the reaction:

2 moles of iron produces 2 moles of iron (ii) oxide.

So, 0.0771 moles of iron will produce = \frac{2}{2}\times 0.0771=0.0771mol of iron (ii) oxide

Now, calculating the theoretical yield of iron (ii) oxide using equation 1, we get:

Moles of of iron (II) oxide = 0.0771 moles

Molar mass of iron (II) oxide = 71.844 g/mol

Putting values in equation 1, we get:  

0.0771mol=\frac{\text{Theoretical yield of iron(ii) oxide}}{71.844g/mol}=5.53g

To calculate the percentage yield of iron (ii) oxide, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield of iron (ii) oxide = 5.17 g

Theoretical yield of iron (ii) oxide = 5.53 g

Putting values in above equation, we get:

\%\text{ yield of iron (ii) oxide}=\frac{5.17g}{5.53g}\times 100\\\\\% \text{yield of iron (ii) oxide}=93.49\%

Hence, the theoretical yield of iron (II) oxide is 5.53g and percent yield of the reaction is 93.49 %

7 0
3 years ago
Which statement is true?
AleksandrR [38]

Exothermic reaction is where there is release of energy during a reaction

The enthalpy of exothermic reaction is negative

The relation between energy of products, reactants and enthalpy of reaction is

Enthalpy of reaction =  sum of enthalpy of formation of products - sum of enthalpy of formation of reactants .

As enthalpy of reaction is negative, it means the enthalpy of products is less than the enthalpy of reactants  so answer is :

In an exothermic reaction the energy of the product is less than the energy of the reactants.

7 0
3 years ago
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The scientific Method
allochka39001 [22]
Observation : a piece of info we all gather through our 5 senses
Hypotheses: a testable explanation for an observation
Data: info that scientists gather during an experiment
Experiment: a procedure that is designed to test a hypothesis
Conclusion a judgment or decision
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4 0
3 years ago
Need help on 17,19,20 please.
pentagon [3]

Answer:

c, maybe d, and I think b.

Explanation:

Im sorry if wrong

5 0
3 years ago
If 54.9 L of an ideal gas is cooled from 64 degrees C to 7 degrees C, what will the volume of the gas become?
sweet [91]

Answer:

Volume = 45.62L

Explanation:

Data;

V1 = 54.9L

T1 = 64°C = (64 + 273.15)k = 337.15K

T2 = 7°C = (7 + 273.15)k = 280.15K

V2 = ?

From Charles law,

The volume of a fixed mass of gas is directly proportional to its temperature provided that pressure remains constant

V = KT, K = V / T = V1 / T1 = V2 / T2 = V3 / T3 =.........= Vn / Tn

(54.9 / 337.15) = (V2 / 280.15)

V2 = (54.9 * 280.15) / 337.15

V2 = 45.618L

V2 = 45.62L

8 0
3 years ago
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