Sounds like a problem in binomial probability. What do you think?
Here the # of experiments is 6, so n = 6. The probability of a baby girl being born is 0.50.
Using my TI-83 Plus calculator:
binompdf(6, 0.5, 2) = 0.234
binompdf(6, 0.5, 3) = 0.313
binompdf(6, 0.5, 4) = 0.234
binompdf(6, 0.5, 5) = 0.094
binompdf(6, 0.5, 6) = 0.016
To get the prob. of at least 2 girls in 6 births, add up the 5 probabilities given above:
P(at least 2 girls in 6 births) = 0. ???
Answer: -2.1p + 1.7
2.4 - 6p - 0.7 + 3.9p
Subtract 6p from 3.9p. (-2.1p)
Subtract 0.7 from 2.4. (1.7)
Answer:
i dont know what the toatle mass of the barries is im preaty sure you are suppost to tell us that so we can awser but what you need to do is...
Step-by-step explanation:
add everything up, the toatle mean add so for example if it is
berry 1=2.64 mass
berry 2=5.93 mass
and berry 3 is 0.96 mass
you need to add everything up
2.64+5.93+0.96 = ?
9.53 that is the toatle mass for my example
WARNING!! do not put this as your awnser this is an example so this is not the answer!!
HOPE THIS HELPS!!
Probability=desired outcomes/total possible outcomes
so
desired outcomes is the 'not wedding' photos
there are 4 vacation and 8 holiday
so 12 'not wedding' photos
12=desired outcomes
total outcomes is 13+4+8=25
so the probablity would be 12/25 or about 48%
Answer:

Step-by-step explanation:
Let
x------> Lamar's collection of cards
The algebraic expression of the phrase "Lamar decreased his collection of cards by seven" is equal to subtract the number seven from Lamar's collection of cards
so
