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Evgen [1.6K]
2 years ago
13

How do I solve this problem using the quadratic formula?

Mathematics
1 answer:
Bond [772]2 years ago
5 0

Answer:

Step-by-step explanation:

a = -3 ; b = -6  ; c = -11

D = b² - 4ac

 = (-6)² - 4*(-3)*(-11)

 = 36 - 132

 = - 96

\sqrt{D}=\sqrt{-96}=\sqrt{96i^{2}} =9.8i

x =\dfrac{-b+\sqrt{D}}{2a} \ ; \ x =\dfrac{-6-\sqrt{D}}{2a}\\\\\\x=\dfrac{6+9.8i}{2*(-3)} \ ; \ x=\dfrac{6-9.8i}{2*(-3)}\\\\\\x=\dfrac{6}{-6}+\dfrac{9.8}{-6}i \ ; \ x=\dfrac{6}{-6}-\dfrac{9.8}{-6}i\\\\\\x=-1-\dfrac{4.9}{3}i \; \ x=-1+\dfrac{4.9}{3}i

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HELPPPPPPPP<br><br> In WXY, y=690 cm, w=440 cm and angle X=163°. Find angle W to the nearest degree
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Answer:

The angle W is approximately 7°.

Step-by-step explanation:

Since angle X is adjacent to sides y and w and opposite to side x, we calculate the length of side x by Law of the Cosine:

x = \sqrt{y^2+w^2-2\cdot y\cdot w \cdot \cos X} (1)

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y, z - Side lengths, in centimeters.

W - Angle, in sexagesimal degrees.

If we know that y = 690\,cm, w = 440\,cm and X = 163^{\circ}, then the length of the side x is:

x = \sqrt{y^2+w^2-2\cdot y\cdot w \cdot \cos X}

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By Geometry we know that sum of internal angles in a triangle equals 180°. If X is an obtuse, then Y and W are both acute angles. By Law of the Sine we find angle W:

\frac{x}{\sin X}= \frac{w}{\sin W} (2)

\sin W = \left(\frac{w}{x} \right)\cdot \sin X

W = \sin^{-1}\left[\left(\frac{w}{x} \right)\cdot \sin X\right]

If we know that X = 163^{\circ}, w = 440\,cm and x\approx 1118.199\,cm, then the angle W is:

W = \sin^{-1}\left[\left(\frac{w}{x} \right)\cdot \sin X\right]

W \approx 6.606^{\circ}

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dsp73

Answer:

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g(12) = √8

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