The area of the shaded region in the task content is; 251.2.
<h3>What is the area of the shaded region in the task content?</h3>
It follows from the task content that the area of the shaded region is;
= Area of semicircle IL - Area of semicircle JK + Area of semicircle IJ + Area of semicircle KL.
Hence, since the radius of each semicircle are as follows;
R(IL) = 12
R(IJ) = R(JK) = R(KL) = 4.
Hence, the Area of the shaded region can be evaluated as;
= (π/2)(12² - 4² + 4² +4²).
= π (144 +16)
= (3.14/2) × 160 = 251.2
Read more on Area of semicircle;
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30 divided by 100 = 0.3 x 7.5 = 2.25 or 25%
So the x-intercept is 3. Also, the y-intercept can also be obtained by putting x=0 in the equation to get y=12/(-6)=-2
