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Svetllana [295]
2 years ago
12

The pH of a solution prepared by dissolving 0. 350 mol of solid methylamine hydrochloride (CH3NH3Cl) in 1. 00 L of 1. 10 M methy

lamine (CH3NH2) is ________. The Kb for methylamine is 4. 40 ⋅ 10-4. (Assume the final volume is 1. 00 L. )
Chemistry
1 answer:
MrMuchimi2 years ago
8 0

For the pH of a solution prepared by dissolving 0. 350 mol of solid methylamine hydrochloride, the pH is mathematically given as

pH = 11.14

<h3>What is the pH value of a solution prepared by dissolving 0. 350 mol ?</h3>

Generally, the equation for the pKb  is mathematically given as

pKb = -logKb

Therefore

pKb of CH3NH2 = -log(4.40×10-4)

pKb of CH3NH2= 3.36

Hence

pKa= 14 - pKb

pKa= 14 - 3.36

pKa= 10.64

In conclusion, using

pH = pKa + log([A-]/[HA])

pH = 10.64 + log(1.10M/0.350M)

pH = 11.14

Read more about pH value

brainly.com/question/1584537

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Analysis of a compound indicates that it contians 1.04 g K, 0.70 g Cr, and 0.86 g O. Find its empirical formula.
Annette [7]

Answer:

K2CrO4

Explanation:

To find the empirical formula, we need to divide each element by its atomic mass. The atomic masses of potassium, chromium and oxygen are 39.0983, 51.9961 and 15.999 respectively. We make the divisions as follows:

K = 1.04/39.0983 = 0.027

Cr = 0.70/51.9961 = 0.013

O = 0.86/15.999 = 0.054

We now divide by the smallest which is the number of moles of the Chromium

K = 0.027/0.013 = 2

Cr = 0.013/0.013 = 1

K = 0.054/0.013 = 4 approximately

The empirical formula is thus:

K2CrO4

7 0
3 years ago
The following reaction was performed in a sealed vessel at 791 ∘C : H2(g)+I2(g)⇌2HI(g) Initially, only H2 and I2 were present at
OlgaM077 [116]

Answer:

4.31 × 10²

Explanation:

Equation of the reaction;

H_{2(g)} + I_{2(g)}     ⇌     2HI_{(g)

The ICE Table is shown as follows:

                            H_{2(g)}         +         I_{2(g)}        ⇌     2HI_{(g)

Initial                    3.10                     2.50                  0      

Change                 - x                       -x                     + 2x      

Equilibrium        (3.10 - x)                0.0800              2x

From I_{2(g)}   ;

We can see that 2.50 - x = 0.0800

So; we can solve for x;

x = 2.50 - 0.0800

x = 2.42

H_{2(g)}  which = (3.10 -x) will be :

= 3.10 - 2.42

= 0.68

2HI_{(g) = 2x

= 2 (2.42)

= 4.84

K_c = \frac{[HI]^2}{[H_2][I_2]}

K_c = \frac{(4.84)^2}{(0.68)(0.0800)}

K_c =\frac{23.4256}{0.0544}

K_c = 430.62

K_c ≅ 431

K_c = 4.31 × 10²

6 0
3 years ago
What is the number of significant figures in 12.0160 mL of water?
likoan [24]

Answer:

To calculate the number of significant figures in a number with decimal,

start at the first non-zero digit in the number and count the total number of digits till the end

hence, in this number:

we will have 6 significant figures

4 0
4 years ago
What’s the mass of a substance that’s density is 100.09g/mL and takes up 52.75mL?
Leokris [45]
Answer: 5,279.7475g

Mass = Density x Volume
Fill in the blanks :D
Mass= 100.09g/mL x 52.75mL

The mL cancels out and you multiply the numbers.
Mass= 5,279.7475 g
5 0
3 years ago
how many molecule of carbon dioxide are needed to react with excess iron oxide to produce 11.6 g of iron
lesya692 [45]

Answer:

0.16 moles of Carbon

Explanation:

The balanced reaction equation:

2Fe_{2}O_{3} + 3C → 4Fe + 3CO_{2}↑

The mole ratio of Carbon to Iron is 3 : 4 (since Fe2O3 is in excess)

i.e 3 moles of C produces 4 moles of Fe.

If 1 mole of Fe - 55.8g of Fe

? moles - 11.6g of Fe

= \frac{11.6}{55.8} = 0.208 moles

But 3 moles of C - 4 moles of Fe

? moles of C - 0.208 moles of Fe

= \frac{3 *0.208}{4} = 0.16 moles of carbon.

I hope this explanation was clear and useful.

5 0
4 years ago
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