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inessss [21]
3 years ago
15

Both Sydney, Australia and Guangzhou, China are on the East coasts of continents in the Pacific Ocean. Why are their yearly temp

eratures opposite? 1 point
A. China in northern hemisphere and Austria in the Southern hemisphere.
B. Opposite summers: Summer in China, winter in Austria.
C. Opposite winters: Winter in Austria, winter in China.
D. All of the above.
Chemistry
1 answer:
cestrela7 [59]3 years ago
6 0

Answer:

All of the above

Explanation:

(I'm assuming you meant to put Australia in the options)

Australia is in the southern hemisphere and has its summer in December etc. and Winter in July etc.

China is in the northern hemisphere and has its summer in July etc and Winter in December etc.

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Please refer to image please
GarryVolchara [31]

Answer:

76.9L

Explanation:

Based on the graph, whenever the temperature increases by 100K, the volume increases by 10L, so do 769/10

7 0
2 years ago
3. The temperature of a fixed mass of gas in a rigid container is decreased from 127.00 degrees
Sonbull [250]

Answer:

750mmHg

Explanation:

The following data were obtained from the question:

T1 = 127°C = 127 +273 = 400K

T2 = 27°C = 27 +273 = 300K

P1 = 1000mmHg

P2 =?

P1/T1 = P2/T2

1000/400 = P2 /300

Cross multiply

400 x P2 = 1000 x 300

Divide both side by 400

P2 = (1000 x 300)/400

P2 = 750mmHg

Therefore, the new pressure after cooling is 750mmHg

5 0
3 years ago
State where the chemical potential energy released from a reaction is stored
Vlad [161]
It is stored in the bonds between atoms.
4 0
3 years ago
Which is a type of star system?
Pepsi [2]

<h2><em>hope my answer is useful..</em></h2><h2><em>hope my answer is useful.. </em></h2>

7 0
2 years ago
If 8.00 g NH4NO3 is dissolved in 1000 g of water, the water decreases in temperature from 21.00 degrees Celsius to 20.39 degrees
telo118 [61]

Answer:

25.7 kJ/mol

Explanation:

There are two heats involved.

heat of solution of NH₄NO₃ + heat from water = 0

q₁  +  q₂  =  0

n  =  moles of NH₄NO₃  =  8.00 g NH₄NO₃  ×  1 mol NH₄NO₃/80.0 g NH₄NO₃          

∴ n =   0.100 mol NH₄NO₃

q₁ = n * ΔHsoln = 0.100 mol * ΔHsoln

m  =  mass of solution  =  1000.0 g + 8.00 g  =  1008.0 g

q₂  =  mcΔT  = 58.0 g  ×  4.184 J°C⁻¹  g⁻¹  × ((20.39-21)°C) = -2570.19 J

q₁  +  q₂  =  0.100 mol  ×ΔHsoln  – 2570.19 J  =  0

ΔHsoln  =  +2570.19 J  /0.100 mol  =  +25702 J/mol  =  +25.7 kJ/mol

7 0
3 years ago
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