Answer:
The thermic effect of food.
Explanation:
The process in which metabolic rate increase after meal is called the THERMIC EFFECT OF FOOD.
THERMICAL EFFECT OF FOOD can be defined as the way in which some calories a person or an individual consumed after meal help to break down the food for easy absorbing and to store the food consumed while some are burn off during execise which is why a person or an individual metabolic rate may elevate after meal, during exercise or due to some other factors reason been that human body makes use of energy everyday due to day to day activities.
Example a person who consumed a protein food may experience high THERMIC EFFECT than the person who consumed food that contained fat or carbohydrates reason been it can take a long time for such person body to break down the food, burn and absorb the protein.
Therefore The increase in metabolic rate after a meal is called THERMIC EFFECT OF FOOD.
Answer:
See below.
Explanation:
The volume increases.
This is complies with Boyles Law:
At constant temperature P1 V1 = P2 V2 where P1, P2 are the pressures before and after and V1 and V2 are the volumes before and after.
The empirical formula : Fe₂O₃
<h3>Further explanation</h3>
Given
34.97g of Iron
15.03g of Oxygen
Required
The empirical formula
Solution
Mol ratio :
Fe(Iron) : 34.97 g : 56 g/mol = 0.624
O(Oxygen) : 15.03 g : 16 g/mol = 0.939
Divide by 0.624 :
Fe : O = 1 : 1.5
Fe : O = 2 : 3
Orbital s is always the first one to fill up
Q1)
molarity is defined as the number of moles of solute in 1 L of solution.
the NaCl solution volume is 1.00 L
number of moles NaCl = NaCl mass present / molar mass of NaCl
NaCl moles = 112 g / 58.5 g/mol = 1.91 mol
the number of moles of NaCl in 1.00 L of solution is - 1.91 mol
therefore molarity of NaCl is 1.91 M
Q2)
molality is defined as the number of moles of solute in 1 kg of solvent.
density is mass per volume.
density of the solution is 1.08 g/mL.
therefore mass of the solution is = density x volume
mass = 1.08 g/mL x 1000 mL = 1080 g
since we have to find the moles in 1 kg of solvent
mass of solvent = 1080 g - 112 g = 968 g
number of moles of NaCl in 968 g of solvent - 1.91 mol
therefore number of NaCl moles in 1000 g - (1.91 mol / 968 g) x 1000 g/kg = 1.97 mol/kg
molality of NaCl solution is 1.97 mol/kg
Q3)
mass percentage is the percentage of mass of solute by total mass of the solution
mass percentage of solution = mass of solute / total mass of the solution
mass of solute = 112 g
total mass of solution = 1080 g
mass % of NaCl = 112 g / 1080 g x 100%
therefore mass % of NaCl = 10.4 %
answer is 10.4 %
