The empirical formula is C₇H₆O₂.
Assume that you have 100 g of the compound.
Then you have 68.84 g C and 4.962 g H.
Mass of O = (100 – 68.84 – 4.962) g = 26.20 g O.
Now, we must convert these masses to moles and find their ratios.
From here on, I like to summarize the calculations in a table.
<u>Element</u> <u>Mass/g</u> <u>Moles</u> <u>Ratio</u> <u> ×2</u> <u>Integers</u>
C 68.84 5.732 3.501 7.001 7
H 4.962 4.923 3.006 6.012 6
O 26.20 1.638 1 2 2
The empirical formula is C₇H₆O₂.
Answer:
Explanation:
Before writing this equation in a molecular equation form, let's identify each species:
- phosphorus is a non-metal represented by 'P', it is solid at standard conditions;
- iron(III) oxide is an ionic compound consisting of iron(III) cations with a 3+ charge, as well as of oxide anions with a 2- charge, this means we may represent it as , which is also a solid material at standard conditions;
- tetraphosphorus decoxide consists of 4 phosphorus atoms and 10 oxygen atoms, as stated by the prefixes, this is also a solid;
- iron metal is simply 'Fe'.
Putting all of this into a single equation and balancing it, we obtain:
I believe the answer would be Neutrons