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Dima020 [189]
2 years ago
11

How many times larger is 8×10^9 than 2×10^7​

Mathematics
1 answer:
elixir [45]2 years ago
7 0

Answer:

It is larger by 4*10^2  times

Step-by-step explanation:

You use exponential division for this problem

first, divide 8 by 2

8/2 = 4

Then, look at 10^9 and 10^7

The bases of those numbers are the same, so you can just subtract the exponents since you're dividing.

10^9 / 10^7 = 10^{9-7} = 10^2

Combine those two together to get:

4 * 10^2

You might be interested in
Zucchini weights are approximately normally distributed with mean 0.8 pound and standard deviation 0.25 pound. Which of the foll
Charra [1.4K]

Answer:

0.81859

Step-by-step explanation:

We solve using z score method

The formula for calculating a z-score is is z = (x-μ)/σ,

where

x is the raw score

μ is the population mean

σ is the population standard deviation.

Mean 0.8 pound

Standard deviation 0.25 pound

For x = 0.55 pound

z = 0.55 - 0.8/0.25

= -1

Probability -value from Z-Table:

P(x = 0.55) = 0.15866

For x = 1.3 pounds

Z = 1.3 = 0.8/0.25

= 2

Probability value from Z-Table:

P(x = 1.3) = 0.97725

The probability that a randomly selected zucchini will weigh between 0.55 pound and 1.3 pounds is

P(x = 1.3) - P(x = 0.8)

0.97725 - 0.15866

0.81859.

6 0
3 years ago
50 POINTS!!!! NEED HELP!!! 2 QUESTIONS!!!! please answer correctly. i begging u
frosja888 [35]
Dawson's annual premium will be $2,462.40. This can be found by going across from "Male 40-44" over to "20-year coverage" which is $13.68. Since $13.68 is per $1000 of coverage, you would multiply it by 180 to get $2,462.40.

Rachel's checks I believe would have a deduction of $63.14.
4 0
3 years ago
Read 2 more answers
What is the sum of 3+(-5)?
pantera1 [17]

Answer:

Your answer is -2 hope this helps

7 0
3 years ago
Read 2 more answers
Student performance across discussion sections: A professor who teaches a large introductory statistics class (197 students) wit
adell [148]

Answer:

The test is not significant at 5% level of significance, hence we conclude that there's no variation among the discussion sections.

Step-by-step explanation:

Assumptions:

1. The sampling from the different discussion sections was independent and random.

2. The populations are normal with means and constant variance

H_0: There's no variation among the discussion sections

H_1: There's variation among the discussion sections

\alpha =0.05

                Df     Sum Sq       Mean sq    F value     Pr(>F)

Section     7       525.01         75             1.87            0.99986

Residuals  189    7584.11        40.13

Test Statistic = F= \frac{75}{40.13} =1.87

Pr(>F) = 0.99986

Since our p-value is greater than our level of significance (0.05), we do not reject the null hypothesis and conclude that there's no significant variation among the eight discussion sections.

3 0
3 years ago
Can anybody teach me how to solve this pls​
wel
Answer is 10 and 170, complementary angles are 90°, while supplementary angles are 180 in total, if angle A is 80 then you subtract 90 by 80 and you get 10, so that is angle B, So then you are asked what is angle C. Which is part of the supplementary angle so you take the 10° that you got from B and then you subtract 180 by the 10, And thats how you get 170 and that's how you know that C is 170 (hope this explanation helps)
3 0
2 years ago
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