All categories

3 years ago

What equation has a graph parallel to the line y=4x+7 and has x-int. of -2

Mathematics

2 answers:

AleksAgata [21]3 years ago

6 0

Answer:

y = 4x + 8

Step-by-step explanation:

parallel lines have the same gradient

So, m = 4

y = 4x + c

(-2,0)

0 = 4(-2) + c

c = 8

y = 4x + 8

bearhunter [10]3 years ago

4 0

Y=4x+8 and the slopes are the same making it parallel

You might be interested in

A square prism measuring 4 ft along each edge of the base and 6ft tall

ki77a [65]

4ft * 4ft * 6ft = 96ft squared

6 0

2 years ago

A bag contains 5 blue marbles, 2black marbles ,and 3 red marbles. A marine is randomly drawn from the bag The probability of not

notka56 [123]

Answer:

80%; 30%

Step-by-step explanation:

There is 5 blue marbles, 2 black marbles, and 3 red marbles. In other words, there is a total of 10 marbles.

There are only 2 black marbles and 8 marbles that are not black. Therefore, the probability of <em>not</em> drawing a black marble is 8/10 or 4/5 or 80%.

There are only 3 red marbles out of the 10 total marbles. Therefore, the probability of drawing a red marble is 3/10 or 30%.

6 0

3 years ago

Find the area of the figure

Paul [167]

The area of the figure is 19.

6 0

3 years ago

Find the values of λ for which the determinant is zero.

elena55 [62]

Answer:

Determinant are special number that can only be defined for square matrices.

Step-by-step explanation:

Determinant are particularly important for analysis. The inverse of a matrix exist, if the determinant is not equal to zero.

How to find determinant

For a 2×2 matrix

$det ( \left[\begin{array}{cc}x&y\\a&z\end{array}\right] ) = xz-ay$

For a 3×3 matrix

we first decompose it to 2×2

$det (\left[\begin{array}{ccc}k&l&m\\o&p&q\\r&s&t\end{array}\right] )\\\\= k*det(\left[\begin{array}{cc}p&q\\s&t\end{array}\right] ) - l*det(\left[\begin{array}{cc}o&q\\r&t\end{array}\right] ) + m*det(\left[\begin{array}{cc}o&p\\r&s\end{array}\right] ) \\\\=k(pt-sq) - l(ot-rq) + m(os-rp)$

Example

Find the values of λ for which the determinant is zero

$\left[\begin{array}{ccc}s&-1&0\\-1&s&-1\\0&-1&1\end{array}\right]$

$det(\left[\begin{array}{ccc}s&-1&0\\-1&s&-1\\0&-1&1\end{array}\right])\\\\= s*det(\left[\begin{array}{cc}s&-1\\-1&1\end{array}\right] ) - (-1)*det(\left[\begin{array}{cc}-1&-1\\0&1\end{array}\right] ) + 0*det(\left[\begin{array}{cc}-1&s\\0&-1\end{array}\right] )\\\\= s(s(1)-(-1*-1)) - (-1)(-1*1 - (-1*0)) + 0\\= s(s - 1)) + 1(-1 + 0) \\=s^{2} -s-1$