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Scilla [17]
2 years ago
7

A 25.00 mL sample of a hydrochloric acid solution was titrated to completion with 34.55 mL of 0.1020 M sodium hydroxide. What wa

s the concentration of the hydrochloric acid
Chemistry
1 answer:
elena-14-01-66 [18.8K]2 years ago
8 0

The concentration of hydrochloric acid with a volume of 25mL titrated with 34.55 mL of 0.1020 M sodium hydroxide is 0.141M.

<h3>How to calculate concentration?</h3>

The concentration of an acid in a titration procedure can be calculated using the following expression:

CaVa = CbVb

Where;

  • Ca = concentration of acid
  • Cb = concentration of base
  • Va = volume of acid
  • Vb = volume of base

  • Ca = ?
  • Cb = 0.102M
  • Va = 25mL
  • Vb = 34.55mL

Ca × 25 = 0.102 × 34.55

25Ca = 3.52

Ca = 0.141M

Therefore, the concentration of hydrochloric acid with a volume of 25mL titrated with 34.55 mL of 0.1020 M sodium hydroxide is 0.141M.

Learn more about concentration at: brainly.com/question/10725862

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3 0
3 years ago
The mole fraction of a non electrolyte (MM 101.1 g/mol) in an aqueous solution is 0.0194. The solution's density is 1.0627 g/mL.
yanalaym [24]

Answer:

Molarity for the solution is 1.05 mol/L

Explanation:

Mole fraction of solute = 0.0194

Solution's density = 1.0627 g/mL

We must know that sum of mole fraction = 1

Mole fraction of solute + Mole fraction of solvent = 1

0.0194 + Mole fraction of solvent = 1

Mole fraction of solvent = 1 - 0.0194 → 0.9806

Molarity is mol of solute in 1L of solution, so we have to determine solution's volume in L

With molar mass we can determine the mass of solute and solvent and then, the solution's mass

0.0194 mol . 101.1 g/ mol = 1.96 g of non electrolyte solute

0.9806 mol . 18 g/mol = 17.65 g of water

Mass of solution = mass of solute + mass of solvent

1.96 g + 17.65 g = 19.6 g (mass of solution)

Solution's density = Solution's mass / Solution's volume

1.0627 g/mL = 19.6 g / Solution's volume

Solution's volume = 19.6 g / 1.0627 g/mol →18.4 mL

Let's convert the mass from mL to L

18.4mL . 1L / 1000 mL = 0.0184 L

We have the moles of solute, so let's determine molarity

mol/L → 0.0194 mol / 0.0184 L =  1.05 M

8 0
3 years ago
Avoltic cell prepared using aluminium and nickle has the flowing cell notation ​
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Answer:

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Explanation:

It seems that you meant "A voltic cell".

Here, Al (s) represents the solid anode while Al³⁺ is in aqueous phase, these two forms are separated by a solid line. || is the salt bridge while Ni²⁺ is in aqueous phase and is reduced on the nickel cathode that is Ni (s).

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How many grams of ammonia (NH3) will produce<br> 300 grams of N2?<br> 4NH3 + 6NO → 5N2 + 6H2O
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Molar mass

NH3 = 17 g/mol
N2 = 28 g/mol

4 NH3 + 6 NO = 5 N2 + 6 H2O

4 x 17 g NH3 ------------ 5 x 28 g N2
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Answer:

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