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kompoz [17]
3 years ago
6

How to solve and respond.

Mathematics
1 answer:
son4ous [18]3 years ago
3 0

Step-by-step explanation:

the error:

it is stated that

\frac{5x}{x+7} +\frac{7}{x} = \frac{5x}{x+7} +\frac{7(7)}{x+7}

subtract (5x)/(x+7) from both sides

\frac{7}{x}  = \frac{7(7)}{x+7}

multiply both sides by x + 7

7(x+7) = 49x

7x + 49 = 49x

subtract 7x from both sides to isolate x and its coefficient

49 = 42x

thus, this is only true when 49 = 42x. in order for these two equations to be equal, they must <em>always </em>be true, so this is wrong

the solution:

we want to express 7/x as (something) / (x+7). to do this, we can multiply 7/x  by 1.

anything divided by itself = 1. thus, if we multiply both the numerator and the denominator by something that turns x into (x+7), we can do what we want to do.

(x+7)/x * x turns x into (x+7), so we multiply both the numerator and denominator by (x+7)/x to get

\frac{7}{x} = \frac{7(x+7)/x}{x+7}

substitute this for 7/x in our original problem

\frac{5x}{x+7} +\frac{7(x+7)/x}{x+7} =  \frac{5x}{x+7} +\frac{(7x+49)/x}{x+7} = \frac{5x}{x+7} +\frac{7+49/x}{x+7} = \frac{5x+7+49/x}{x+7}

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Five siblings have a combined age of 195 years. The oldest is 13 years older than the youngest Marc the middle child Anne is fiv
lidiya [134]
This is what someone else answered when someone else asked it. I can't explain it better than this.





So five sibbllings ages are repressented as
a,b,c,d,e
let's have a as youngest and e as oldest in that order
total ages are 195 so
a+b+c+d+e=195
oldest is 13 older thatn youngest
e=13+a
middle child anne (c) is 5 years younger than josie who is an unknow position, we know that she could be d or e or oldest or second oldest
the other 2 are 6 years appart
b and d ar e 6 years appart or b and e are 6 years apart? or is josie the oldest, or second oldest?

second oldes is 42 so
d=42

2 scenarios
if josie is oldest, then see AAAA and if josie is second oldest then see BBBB

AAAA
josie is 13 years older than mark
e=13+a
anne is 5 less than josie
c=e-5
the other 2 are 6 years apart
b+6=d
d=42
subsitute and get
b=36
add and get
78+a+c+e=195
a+c+e=117
e-13+e-5+e=117
3e-18=117
add 18 to both sides
3e=135
divided both sides by 3
e=45
subsitute
a=32
b=36
c=40
d=42
e=45


BBBB
oldest is 13 older than youngest
e=13+a
middle is 5 younger than josie (d)
c=d-5
the other 2 are 6 apart
b=e-6
d=42
subsitute
c=37
subsitute
a+b+37+42+e=195
a+b+e+79=195
subtract 79 from both sides
a+b+e=116
subsitute
e-13+e-6+e=116
3e-19=116
add 19 to both sides
3e=135
divide both sides by 3
e=45
subsitute
45-6=39=b
45-13=32=a
c=42-5=37
this is wrong because b cannot be older than c so therefor AAA si the correct answer


THE ANSWER IS
Josie is the oldest=45
Unknown is second oldest=42
Anne is middle=40
Unknown2 is second youngest=36
Mark is the youngest=32
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