I'll show a step-by-step. I'm not in the mood to explain right now lol.
2(x-2.6)+2.91=7.71
2x-5.2+2.91=7.71
+5.20 +5.20
2x+2.91=12.91
-2.91 -2.91
2x=10
/2 /2
x=5
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hope it helps
sorry if it doesn't
Question:
You are in a bike race. When you get to the first checkpoint, you are 2/5 of the distance to the second checkpoint. When you get to the second check point, you are 1/4 of the distance to the finish. If the entire race is 40 miles, what is the distance between the start and the first check point?
Answer: 4 miles
Step-by-step explanation:
Let distance between start to first checkpoint = x
First checkpoint to second checkpoint = 2/5 of x
Distance of start to checkpoint 1 = ( 2/5 of start to checkpoint 2)
Distance of start to checkpoint 2 = (1/4 of start to finish)
If start to checkpoint 2 = 1/4 of start to finish
Then,
Distance of start to checkpoint 1 = ( 2/5 * 1/4 of start to finish)
Distance of start to checkpoint 1 = 2/20 of start to finish = 1/10 of start to finish
Entire race = 40 miles = distance from start to finish
1/ 10 of 40
= ( 1/10) × 40
= 4 miles
Answer:
sin A = 13/85
Step-by-step explanation:
Opposite Angle A is side BC, of length 13. The length of the hypotenuse is 85. The sine function is defined as the ratio opp/hyp. In this problem that ratio is
opp
------ = sin A = 13/85
hyp
We use the inverse sine function arcsin x to determine Angle A:
A = arcsin 13/85 = 8.8 degrees
-3(6-10v-5v)
=-3(6-15v)
=-18+45v
-18+45v is the final answer.
