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ivolga24 [154]
2 years ago
12

How many liters of 2.0 M NaCl solution can be made from 0.75 moles of NaCl

Chemistry
1 answer:
andreyandreev [35.5K]2 years ago
5 0

Answer: B) 0.38L

Explanation: I really hope this helps XDDD

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methane Express your answer as a condensed structural formula omitting all bonds (e.g CH3CH2CH3). nothing Request Answer Part B
bonufazy [111]

Answer:

a

 The condensed structural formula for methane is

            CH_4

b

 The condensed structural formula for ethane is

           CH_3 CH_3

c

  The condensed structural formula for pentane is  

            CH_2(CH_2)_3CH_3

d

   The diagram for the structural formula for cyclopropane is shown on the first uploaded image

Explanation:

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4 years ago
Draw the most stable conformation of 3-isopropyl-1,1dimethylcyclohexane Please show me which one is the isopropyl and the dimeth
Andrei [34K]

The most stable conformation of 3-isopropyl-1,1dimethylcyclohexane equatorial ethyl group (more stable).  The stability of ethylcyclohexane's equatorial conformer exceeds that of its axial conformer by 7.4 kJ/mol.

According to the previous section, the chair conformation with the equatorial methyl group is more stable because it reduces steric repulsion, and as a result, the equilibrium favors the more stable conformer. Strongly favoring the equatorial shape is methylcyclohexane. The methyl group is in close proximity to the axial hydrogens in the axial conformation, which has an energetically unfavorable effect known as a 1,3-diaxial interaction. The methyl group prefers the equatorial shape as a result.  The conformation of ethylcyclohexane in which the ethyl group is in the equatorial position is the most stable.

Learn more about equatorial ethyl group here:

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7 0
1 year ago
How many grams are in 2 moles of FeH3?
pshichka [43]

Answer:335.07

Explanation:

3 0
3 years ago
Read 2 more answers
A sample of CaCO3 (molar mass 100. g) was reported as being 30. percent Ca. Assuming no calcium was present in any impurities, c
natka813 [3]

Answer:

Approximately 75%.

Explanation:

Look up the relative atomic mass of Ca on a modern periodic table:

  • Ca: 40.078.

There are one mole of Ca atoms in each mole of CaCO₃ formula unit.

  • The mass of one mole of CaCO₃ is the same as the molar mass of this compound: \rm 100\; g.
  • The mass of one mole of Ca atoms is (numerically) the same as the relative atomic mass of this element: \rm 40.078\; g.

Calculate the mass ratio of Ca in a pure sample of CaCO₃:

\displaystyle \frac{m(\mathrm{Ca})}{m\left(\mathrm{CaCO_3}\right)} = \frac{40.078}{100} \approx \frac{2}{5}.

Let the mass of the sample be 100 g. This sample of CaCO₃ contains 30% Ca by mass. In that 100 grams of this sample, there would be \rm 30 \% \times 100\; g = 30\; g of Ca atoms. Assuming that the impurity does not contain any Ca. In other words, all these Ca atoms belong to CaCO₃. Apply the ratio \displaystyle \frac{m(\mathrm{Ca})}{m\left(\mathrm{CaCO_3}\right)} \approx \frac{2}{5}:

\begin{aligned} m\left(\mathrm{CaCO_3}\right) &= m(\mathrm{Ca})\left/\frac{m(\mathrm{Ca})}{m\left(\mathrm{CaCO_3}\right)}\right. \cr &\approx 30\; \rm g \left/ \frac{2}{5}\right. \cr &= 75\; \rm g \end{aligned}.

In other words, by these assumptions, 100 grams of this sample would contain 75 grams of CaCO₃. The percentage mass of CaCO₃ in this sample would thus be equal to:

\displaystyle 100\%\times \frac{m\left(\mathrm{CaCO_3}\right)}{m(\text{sample})} = \frac{75}{100} = 75\%.

3 0
3 years ago
Some chemical changes can be ______________ through another _______________ change.
zalisa [80]
Some chemical changes can be reactive through another chemical change?
3 0
3 years ago
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