Answer:
The pH for a 0.117 M solution of NaHA is 2.227
Explanation:
To solve the question we check the difference in the Ka values thus
Ka₁ / Ka₂ = 7500000 < 10⁸ so we are required to calculate each value as follows
We therefore have
H₂X→ H⁺¹+HX⁻¹ with Ka₁ = 3.0 × 10⁻⁴
Therefore
3.0 × 10⁻⁴ = (x²)/(0.117)
x² = 3.0 × 10⁻⁴ ×0.117 and x = 5.925 × 10⁻³ = [H⁺]
Similarly
Ka₂ = 4.0 × 10⁻¹¹
and
4.0 × 10⁻¹¹= (x²)/(0.117)
x²= 0.117× 4.0 × 10⁻¹¹
x= 2.16× 10⁻⁶
Total H⁺ = 5.925 × 10⁻³+2.16× 10⁻⁶ = 5.927 × 10⁻³
Since pH = -log of hydrogen ion concentration,
pH = - log 5.927 × 10⁻³ = 2.227
Answer:
A binary ionic compound contains an ion that is a metal (cation) and an ion that is a nonmetal (anion).
Explanation:
Tell me if its wrong
Answer:
a. 2NAOH + H2SO4 —> NA2SO4 + 2H2O
b. The concentration of the acid is 0.0638M
Explanation:Please see attachment for explanation
Answer:
pH>7
sour taste
donate H+ ions
turn litmus paper from blue to red
Explanation:
