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3 years ago

See question in image and show workings

Mathematics

1 answer:

Ivan3 years ago

6 0

Answer:

The equator has the length:

C = 2πr, where π = 22/7, r = 6400 km
C = 2*22/7*6400 = 40228.57 km (rounded)

a) Consider X and Y as two points on the circle with C = 40228.57 km.

The distance between X and Y is:

d = C*(123 - 67)/360
d = 40228.57*56/360 = 6257.78 km (rounded)

b) Since both X and Y are on the equator, they are at the same distance from the north pole, N.

NX makes 90 degrees:

NX = C*90/360
NX = 40228.57*1/4 = 10057.14 km (rounded)

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Take the derivative again:

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Take the derivative one more time:

$\displaystyle\frac{(1+2x)(1-x)^3+3(x+x^2)(1-x)^2}{(1-x)^6}=\sum_{k\ge0}k^3x^{k-1}=\frac1x\sum_{k\ge0}k^3x^k$

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4 years ago

See question in image and show workings​

See question in image and show workings