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Gnom [1K]
2 years ago
14

Courtney has baked some cookies for her friends. On the platter, there are 16 oatmeal cookies, 12 peanut butter cookies, and

Mathematics
1 answer:
inessss [21]2 years ago
6 0

Answer:

The answer would be OA. PO and G) = 0.67

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CINDY made costume decorations. She used 1/10 of a meter of ribbon for each decoration which she got by cutting 3/10 of a meter
Brilliant_brown [7]

Answer:

Cindy made 3 decorations with the ribbons

Step-by-step explanation:

Since Cindy used 1/10 of a metre of ribbon to make just one decoration that she obtained by dividing 3/10 of a meter of ribbon into equal parts, then we can calculate the number of decorations that Cindy made. In this scenario, all we need is an idea on how to divide fractions and we are good to go.

If Cindy used 1/10 of a metre obtained by dividing 3/10 of a metre of ribbon to make decorations, then the number of decorations she made can be gotten by dividing 3/10 by 1/10

i.e 3/10 ÷ 1/10

= 3/10 × 10/1

= 3 decorations.

That is she used 1/10 + 1/10 + 1/10 = 3/10 to make (3 decorations).

3 0
3 years ago
Read 2 more answers
What is the answer A, B, C, or D
adell [148]

The answer would have to be

D


7 0
3 years ago
The solution to which system of equations has an x-value of 3?
ANEK [815]

Answer:

D)

Step-by-step explanation:

7 0
2 years ago
How much more area does a 40 mile radius cover than a 4 mile radius
malfutka [58]
40 mile radius covers 10 times more than 4 mile radius
5 0
3 years ago
We select n + 1 different integers from the set { 1 , 2 , ··· , 2 n } . Provethat there will alwaysbe two among the selected inte
just olya [345]

Answer:

See answer below

Step-by-step explanation:

From the set

{1,2,3,4...2n} we have 2n numbers in total , n are odd and n are even , therefore for a sample of n+1 numbers , we have at least 1 even number and 1 odd number.

Then

it the set includes 1 , the largest common divisor is 1 for 1 and the other numbers

if the set includes 3, there will be always a number that is not divisible by 3. Even we construct a set of n+1 numbers that are multiple of 3 , the largest number would be 3*(n+1)= 3*n+3 > 2*n (out of bounds) , therefore we are forced to take other number that is not divisible by 3  → the largest common divisor of that number with 3 is 1

If the set includes any other prime number → the largest common divisor of that with any other is 1

For the remaining odd numbers N, they can be factorised into other 2 odd common divisors N₂ and n₂ :

N = N₂*n₂ , since n₂ ≥ 2 →  N₂ < N

then the even N₂ also should be contained in the set

therefore also for N₂

N = N₃*n₃ →  N₃ < N₂

therefore if we continue , we would obtain a number  even Nn that has no smaller common divisors → since we cannot take all the multiples of N min ( because Nmin*(n+1)= Nmin*n+Nmin > 2*n for Nmin≥2) → there is at least a number in the sample of n+1 integers whose largest common divisor is 1

6 0
3 years ago
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