Let K=average weight of an okapi and L=that of a llama.
3L=K+190 and K+L=450 so K=450-L. Therefore 3L=450-L+190, 4L=640, L=160kg and K=450-160=290kg.
Okapi weighs 290kg, llama weighs 160kg.
Answer:
-13/8
Step-by-step explanation:
u divied by -8 to get n by itself
Given the function:
The function can also be written as:
The range of the function will be all set of y values.
To find the range, let's graph the function below.
We have:
From the graph above, all possibe y values range from 0 to infinity.
Therefore, the range of the function is from zero infinity.
In interval notation:
Range = (0, +∞)
ANSWER:
4. (0, +∞)
<span>Simplifying
4x2 + -24x + 4y2 + 72y = 76
Reorder the terms:
-24x + 4x2 + 72y + 4y2 = 76
Solving
-24x + 4x2 + 72y + 4y2 = 76
Solving for variable 'x'.
Reorder the terms:
-76 + -24x + 4x2 + 72y + 4y2 = 76 + -76
Combine like terms: 76 + -76 = 0
-76 + -24x + 4x2 + 72y + 4y2 = 0
Factor out the Greatest Common Factor (GCF), '4'.
4(-19 + -6x + x2 + 18y + y2) = 0
Ignore the factor 4.
</span><span>Subproblem 1
Set the factor '(-19 + -6x + x2 + 18y + y2)' equal to zero and attempt to solve:
Simplifying
-19 + -6x + x2 + 18y + y2 = 0
Solving
-19 + -6x + x2 + 18y + y2 = 0
The solution to this equation could not be determined.
This subproblem is being ignored because a solution could not be determined.
The solution to this equation could not be determined.</span>
