Hello,
f(1)=160
f(2)=160*(-2)
f(3)=160*(-2)²
f(4)=160*(-2)^3=-1280
f(n)=160*(-2)^(n-1)
Answer:
t = 64
Step-by-step explanation:
t = 16 × 4
16 × 4 = 64
hope this helps...
Answer:
x= 47
18+2 201 i ≈0.382978723+0.603295612i
x= 47
−2 201 i+18 ≈0.382978723−0.603295612i Hopefully this makes just the same amount of sense as this question
Let the first number be 'x' and the second number is 'y'
Equation 1: x + y = 52
Equation 2: x - y = 38
Rearranging equation 2 to make either x or y the subject
x = 38 + y
Substituting x = 38 + y into equation 1
x + y = 52
(38+y) + y = 52
38 + 2y = 52
2y = 52 - 38
2y = 14
y = 7
Substitute y = 7 into either equation 1 or equation 2 to find x
x + y = 52
x + 7 = 52
x = 52 - 7
x = 45
x = 45
y = 7
All we can determine from the information that you have given us is that
yz should be proportionally related to bc, because their triangles are similar.
