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Lesechka [4]
2 years ago
8

Cyanide and water react in a proton transfer reaction to form hydrogen cyanide and hydroxide

Chemistry
2 answers:
alukav5142 [94]2 years ago
4 0

The proton transfer reaction between Cyanide and water can be written as; X^- + H2O -----> HX + OH^-

<h3>What is a proton transfer reaction?</h3>

A proton transfer reaction is one in which a proton is moved from one chemical specie to another.It is in fact and acid - base reaction in the Brownstead - Lowry sense.

The proton transfer reaction between Cyanide and water can be written as(Let the cyanide ion be shown as X);

X^- + H2O -----> HX + OH^-

Learn more about proton transfer: brainly.com/question/861100?

Rufina [12.5K]2 years ago
4 0

The proton transfer reaction to form hydrogen cyanide and hydroxide is

X⁻ + H₂O → HX + OH⁻

<h3>What is a proton transfer reaction?</h3>

A reaction in which a proton H⁻ is removed from one species and accepted by another species.

An example of a proton transfer is Brønsted acid reacting with a Brønsted base.

Thus, the proton transfer reaction to form hydrogen cyanide and hydroxide is X⁻ + H₂O → HX + OH⁻

Learn more about proton transfer

brainly.com/question/861100

#SPJ4

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If a volume of gas 177.6mL was collected at a temperature of 25.8C and the pressure is 799.7 torr, what is the original concentr
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Answer:

The original concentration of the acid was 0.605 M

Explanation:

Step 1: Data given

Volume of gas = 177.6 mL = 0.1176 L

Temperature = 25.8 °C = 298.95 K

Pressure = 799.7 torr = 799.7/ 760 = 1.0522368 atm

Volume of acid needed to react = 12.6 mL = 0.0126 L

Step 2: Calculate moles

p*V = n*R*T

n = (p*V)/(R*T)

⇒with n = the number of moles = TO BE DETERMINED

⇒with p = the pressure of the gas = 799.7 torr = 1.0522368 atm

⇒with V = the volume of the gas = 177.6 mL = 0.1776 L

⇒with R = the gas constant = 0.08206 L*atm/mol*K

⇒with T = the temperature = 25.8 °C = 298.95 K

n = 0.007618 moles

Step 3: Calculate original concentration

We need 0.007618 moles of acid to react with the same amount of moles gas

Concentration acid = moles / volume

Concentration acid = 0.007618 moles / 0.0126 L

Concentration acid = 0.605 M

The original concentration of the acid was 0.605 M

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