Answer:
i think the answer will be b. the point where the ph corresponds to a solution of the conjugate acid (bh+) in water;
Explanation:
Answer : The energy of the photon emitted is, -12.1 eV
Explanation :
First we have to calculate the 
orbit of hydrogen atom.
Formula used :
where,
= energy of 
orbit
n = number of orbit
Z = atomic number of hydrogen atom = 1
Energy of n = 1 in an hydrogen atom:
Energy of n = 2 in an hydrogen atom:
Energy change transition from n = 1 to n = 3 occurs.
Let energy change be E.
The negative sign indicates that energy of the photon emitted.
Thus, the energy of the photon emitted is, -12.1 eV
Explanation:
here is your answer. Hope it helps
You can't calculate the electronegativity difference of a single molecule you'll need a frame of reference to explain the electronegativity difference and properties arising due to the difference. Another term arise here is modified electronegativity that is calculated within the molecule between two atoms of different electronegativity and use to explain the nature of molecule wether they are electron withdrawing group or electron donating group and also used to compare the electronegativity with other molecule!
