Answer:
Group 2A, Period 6
Explanation:
To know where an atom is located, we need to see its electronic distribution. The major number in it will be the period (not necessary is the number of the valence, because subshell 4s is less energetic than 3d, so it will occur first!).
To know the group, we need to check the subshell more energetic, if is subshell <em>s</em>, it will be in group 1A or 2A, if it has only 1 valence electron, then its group 1A, with two valence electrons, is group 2A.
If the subshell more energetic is the subshell <em>p</em>, so it will be from 3A to 8A, we just add the number of electrons of subshell <em>p</em> with the numbers of electrons of subshell <em>s</em> of the same layer, and we'll have the number of the group.
If the subshell more energetic is the subshell <em>d</em>, it will be in group B, and the number of electrons will be the number of the group.
If the subshell more energetic is subshell <em>f</em>, then it is on group 3B, because will be in latanids or actinides.
So, Barium has the subshell 6s with 2 valence electrons, then it is in group 2A, Period 6.