1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
olga2289 [7]
3 years ago
7

Barium (Ba) has two valence electrons, and these electrons are located in the 6s subshell. Without using the periodic table, in

which group and period is barium located?
Group 2A, Period 7

Group 1A, Period 6

Group 1A, Period 7

Group 2A, Period 6
Chemistry
2 answers:
Katena32 [7]3 years ago
7 0
Barium is located in Group 2A, Period 6
artcher [175]3 years ago
5 0

Answer:

Group 2A, Period 6

Explanation:

To know where an atom is located, we need to see its electronic distribution. The major number in it will be the period (not necessary is the number of the valence, because subshell 4s is less energetic than 3d, so it will occur first!).

To know the group, we need to check the subshell more energetic, if is subshell <em>s</em>, it will be in group 1A or 2A, if it has only 1 valence electron, then its group 1A, with two valence electrons, is group 2A.

If the subshell more energetic is the subshell <em>p</em>, so it will be from 3A to 8A, we just add the number of electrons of subshell <em>p</em> with the numbers of electrons of subshell <em>s</em> of the same layer, and we'll have the number of the group.

If the subshell more energetic is the subshell <em>d</em>, it will be in group B, and the number of electrons will be the number of the group.

If the subshell more energetic is subshell <em>f</em>, then it is on group 3B, because will be in latanids or actinides.

So, Barium has the subshell 6s with 2 valence electrons, then it is in group 2A, Period 6.

You might be interested in
Select the answer which shows the correct order, slowest to fastest, of the relative rate of diffusion of the gases.
IrinaK [193]

Diffusion is the process of a substance spreading out to evenly fill its container or environment. Rate of diffusion of a gas is inversely proportional to the molar mass of the gas.

Rate of diffusion \propto \frac{1}{Molar mass}

Lighter(lower) the molar mass of the gas , faster will be its rate of diffusion and heavier (higher) the molar mass of the gas , slower will be its rate of diffusion.

We have to arrange the given gases from slowest rate of diffusion to fastest rate of diffusion that means we need to arrange gases from higher molar mass to lower molar mass.

Molar mass of given gases are :

Cl = 35.5 g/mol

Xe = 131.29 g/mol

He = 4.00 g/mol

N = 14.00 g/mol

So correct order for slowest rate of diffusion (highest molar mass) to fastest rate of diffusion (lowest molar mass) is :

Xe , Cl , N , He

Xe having the highest molar mass will have the slowest rate of diffusion and He with lowest molar mass will have the fastest rate of diffusion, so option 'c' is correct.

Note : Slowest rate of diffusion = High Molar Mass

Fastest rate of diffusion = Low Molar Mass



7 0
4 years ago
AgBr+Cl2=AgCl+Br2 <br><br><br> REDOX!! HELP PLZ A LOT OF POINTS
mars1129 [50]

2AgBr+Cl2=2AgCl+Br2

You want everything to be the same on both sides the easiest way to do that is draw a line down the equal sign and write out all you compound and how many there are and do the same on the other side until there even

4 0
3 years ago
If the density of an object is 60 g/cm 3 and its mass 20 grams what is its coulume in cm 3
Licemer1 [7]
3 cubic centimeters, Volume= density/ mass





7 0
4 years ago
What mass of iron(II) oxide must be used in the reaction given by the equation below to release 44.7 kJ? 6FeO(s) + O2(g) =&gt; 2
zavuch27 [327]

<u>Answer:</u> The mass of iron (II) oxide that must be used in the reaction is 30.37

<u>Explanation:</u>

The given chemical reaction follows:

6FeO(s)+O_2(g)\rightarrow 2Fe_3O_4(s);\Delta H^o=-635kJ

By Stoichiometry of the reaction:

When 635 kJ of energy is released, 6 moles of iron (II) oxide is reacted.

So, when 44.7 kJ of energy is released, \frac{6}{635}\times 44.7=0.423mol of iron (II) oxide is reacted.

Now, calculating the mass of iron (II) oxide by using the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of iron (II) oxide = 0.423 moles

Molar mass of iron (II) oxide = 71.8 g/mol

Putting values in above equation, we get:

0.423mol=\frac{\text{Mass of FeO}}{71.8g/mol}\\\\\text{Mass of FeO}=(0.423mol\times 71.8g/mol)=30.37g

Hence, the mass of iron (II) oxide that must be used in the reaction is 30.37

7 0
4 years ago
What is a good title for this chart?
Elina [12.6K]

Answer:

pH of the acid

Explanation:

8 0
3 years ago
Other questions:
  • The density of copper is 8.92 g/cm^3. If you plotted the mass of copper in grams versus the volume in cubic centimeters, what wo
    14·1 answer
  • Coke is an impure form of carbon that is often used in the in- dustrial production of metals from their oxides. If a sample of c
    7·1 answer
  • Which best explains why water is able to “stick” to the side of glass?
    10·1 answer
  • A potassium hydroxide (KOH) solution has a molar concentration of 0.065 M, calculate the [H3O+], [OH-] and pH of the solution.
    12·1 answer
  • while looking at calcuim (Ca) on the periodic table a student needs to find with a greater atomic mass in the same period.Where
    12·2 answers
  • Intermolecular forces allow which of the following substances to be the least fluid?
    12·2 answers
  • If I have a 200 L container filled with nitrogen at a pressure of 1.0 atm, how many moles
    6·1 answer
  • What are the three types of diagrams in science? This if eight grade science
    7·1 answer
  • Two substances (A and B) are placed at each end of a glass tube. The vapors of the substances form a solid that is closer to sub
    6·1 answer
  • Why is the atomic model the foundation for chemistry?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!