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In-s [12.5K]
2 years ago
8

How could you “supersaturate” solutions, exceeding the amount of dissolved solute possible

Chemistry
1 answer:
Bingel [31]2 years ago
4 0

Answer:

Explanation:

In a saturated solution, more solute cannot be dissolved at a given temperature.

This is because, the solute dissolves in a solvent because of space between particles of solvent but on continuous addition of solute, the space between the solvent particles gets fulfilled. Thus no more solute particle can dissolve in a solvent.

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State 2 postulates of kinetic theory of gases of 45 of 450
Ber [7]

Explanation:

The kinetic theory of gases is basically used to explain the behavior of gases.

Some of the assumptions of the theory is as follow:

  • A gas is composed of large number of identical molecules at different speeds.
  • The space occupied by the gas molecules themselves are negligible compared to the volume of the space they occupy.
  • The molecules are independent of each other and the force of attraction and repulsion between them are negligible.
  • The molecules collide elastically with one another and with the walls of the container.
  • The temperature of gas is a measure of their average kinetic energy.

learn more:

molecular theory brainly.com/question/12362857

#learnwithBrainly

8 0
2 years ago
How many moles of Hydrogen gas will be produced if you start with 2.5 moles of Magnesium and an excess of Hydrochloric Acid give
stira [4]

Answer:

D.) 2.5 moles

Explanation:

To find the moles of H₂, you need to multiply the given value by the mole-to-mole ratio. This ratio consists of the coefficients in front of the relevant molecules. It is important to arrange the ratio in a way that allows for the cancellation of units.

1 Mg + 2 HCl -----> MgCl₂ + 1 H₂
^                                            ^

2.5 moles Mg            1 moles H₂
-----------------------  x  ---------------------  =  2.5 moles H₂
                                   1 mole Mg

5 0
1 year ago
Calculate the molar mass of aluminum oxide (Al2O3). Express your answer to four significant figures.
a_sh-v [17]

Answer:

102.0 g/mol.

Explanation:

Aluminum oxide  or Al2O3 is a chemical compound composed of 3 Oxygen and 2 aluminum atoms. Naturally, it is present in the form of mineral corundum in crystalline polymorphic forms. It holds significant importance in the preparation of Aluminium metal that is used as a refractory material.

To calculate the molar mass of Aluminum oxide, we will add the molar mass of 2 Al and 3 O atoms.

                         Since molar mass of Al is: 26.98 g

                               Molar mass of O is: 16.00 g

                                   Molar mass of Al2O3

                                  =   (26.98)2 +  (16.00) 3

                                     =    53.96 +   48

                                       = 101.96 g/mol

Since it is mentioned in question to round off the answer upto 4 significant figures, it will make the answer: 102.0 g/mol.

Hope it help!

6 0
3 years ago
A compound has an empirical formula of
Ksju [112]

Answer: C12H12N2O2 (Cyclomethyltryptophan)

8 0
2 years ago
Read 2 more answers
Formula los siguientes compuesto: Dietil eter, Etanol, Propanotriol, Acido Propanodioico, Pentanal, Pentano-2,4-diona, Metanoato
9966 [12]

Answer:

Explanation:

En este caso para formular los compuestos, debes identificar el grupo funcional principal de la molecula. Una vez que eso está hecho, puedes intentar formularlo.

Empezaremos primero identificando el grupo funcional principal de la molécula, para luego formularlo correctamente.

Dietil eter: la terminación eter al final significa que pertenece al grupo de los éteres, el cual tiene como formula general R - O - R.

Etanol: debido a que termina en ol, este grupo pertenece a los alcoholes. Para formularlo solo se dibuja la molecula del etano, junto a un enlace con el grupo OH, como su formula general R - OH.

Propanotriol: igualmente termina en ol, por lo tanto es un alcohol, sin embargo, en este caso, tambien tiene la terminación prefija tri, asi que significa que hay 3 grupos OH en la molecula.

Acido propanodioico: esta es sencilla, porque empieza como acido, y solo hay un grupo funcional que empieza así y son los acidos carboxilicos, es decir, el grupo COOH (R - COOH) que es el carboxilo. Tiene el prefijo di, antes del oico, por lo que son dos carboxilos presentes en la molecula.

Pentanal: el sufijo al, significa que pertenece al grupo de los aldehidos, en este caso, posee el grupo carbonilo H - C = O.

Pentano - 2,4 - diona: la terminación ona significa que pertenece al grupo de las cetonas, (R - CO - R), parecido a los aldehidos, con la diferencia de que tiene grupos alquilos en lugar de un hidrogeno.

Metanoato de metilo: la terminación ato de ilo, pertenece a los esteres, (R - COOR) derivado de los acidos carboxilicos.

De aqui en adelante solo mencionaré los grupos funcionales pues ya se explicó el por que, por sus terminaciones:

Ciclohexano - 1.3 - diol: este pertenece a los alcoholes.

Acido heptanoico: acido carboxilico

Ciclobutil metil eter: eteres

Acetato de etilo: ester

2-metilbenzaldehído: aldehído unido a un grupo aromatico como el benceno.

Ciclohexanona: un ciclo (cadena cerrada) unido a un grupo carbonilo.

Butanona: cetona.

Observa la foto adjunta para que veas la formulación de cada una:

5 0
3 years ago
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