Answer:
19w-11
Step-by-step explanation:
Answer:
Given that,
The number of grams A of a certain radioactive substance present at time, in years
from the present, t is given by the formula

a) To find the initial amount of this substance
At t=0, we get


We know that e^0=1 ( anything to the power zero is 1)
we get,

The initial amount of the substance is 45 grams
b)To find thehalf-life of this substance
To find t when the substance becames half the amount.
A=45/2
Substitute this we get,


Taking natural logarithm on both sides we get,







Half-life of this substance is 154.02
c) To find the amount of substance will be present around in 2500 years
Put t=2500
we get,




The amount of substance will be present around in 2500 years is 0.000585 grams
Answer:
b=1
Step-by-step explanation:
-11+3(b+5)=7
-11+3b+15=7
-11+15+3b=7
4+3b=7
3b=7-4
3b=3
3b/3=3/3
b=1
hope it's helpful
Answer:
you average the scores by adding scores from exam 1 and exam 2 then divide it by 2 to average the exam scores
Step-by-step explanation: