Answer:
Now we can calculate the p value based on the alternative hypothesis with this probability:
The p value is very low compared to the significance level of
then we can reject the null hypothesis and we can conclude that the true proportion of people liberal is higher than 0.24
Step-by-step explanation:
Information given
n=200 represent the random sample taken
X=75 represent the number of people Liberal
estimated proportion of people liberal
is the value that we want to test
z would represent the statistic
represent the p value
Hypothesis to test
We want to verify if the true proportion of adults liberal is higher than 0.24:
Null hypothesis:
Alternative hypothesis:
The statistic is given by:
(1)
Replacing the info given we got:
Now we can calculate the p value based on the alternative hypothesis with this probability:
The p value is very low compared to the significance level of
then we can reject the null hypothesis and we can conclude that the true proportion of people liberal is higher than 0.24
Given:
The graph of a function
.
To find:
The interval where
.
Solution:
From the given graph graph it is clear that, the function before x=0 and after x=3.6 lies above the x-axis. So,
for
and
.
The function between x=0 and x=3.6 lies below the x-axis. So,
for
.
Now,
For
, the graph of h(x) is above the x-axis. So,
.
For
, the graph of h(x) is below the x-axis. So,
.
For
, the graph of h(x) is below the x-axis. So,
.
Only for the interval
, we get
.
Therefore, the correct option is A.
5 boys play both hockey and volleyball (30-20-15=5)
I don't understand what the question is.. there are no spaces..
Step-by-step explanation:
given :
2x - 3y = 11
-6x + 8y = 34
find : the solutions of the system by using Cramers Rule.
solutions:
in the matrix 2x2 form =>
[ 2 -3] [x] [11]
=
[-6 8] [ y] [34]
D =
| 2 -3 |
|-6 8 |
= 8×2 - (-3) (-6)
= 16-18 = -2
Dx = | 11 -3 |
| 34 8 |
= 11×8 - (-3) (34)
= 88 + 102
= 190
Dy = | 2 11 |
|-6 34 |
= 2×34 - (-6) (11)
= 68 + 66
= 134
x = Dx/D = 190/-2 = -95
y = Dy/D = 134/-2 = -67
the solutions = {-95, -67}