(a) Joydeep receives a normal hourly wage of $18.60 and time-and-a-half for

Mathematics

1 answer:

Viktor [21]2 years ago

4 0

Answer:

I'm sorry I don't understand you can give me anything other than math

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Keisha the trainer has two solo workout plans that she offers her clients: Plan A and Plan B. Each client does either one or the

gregori [183]

Answer:

Plan A last 0.75 hours or 45 minutes.

Plan B last 1.5 hours or 90 minutes.

Step-by-step explanation:

Let $a$ be the number of hours that the plan A last, an $b$ the number of hours of plan B. Then for the Wednesday you have:

$2a+3b=6$

And for the Thursday is:

$6a+5b=12$

Multiply the equation of Wednesday by -3:

$-6a-9b=-18$

Using the method of addition using this last equation and the equation of Thursday

$-6a-9b=-18\\6a+5b=12\\--------\\-4b=-6\\b=\frac{-6}{-4}\\b=1.5 hours$

Replacing the value of $b$ in one of the equations

$6a+5b=12\\6a+5(1.5)=12\\6a+7.5=12\\6a=12-7.5\\a=\frac{4.5}{6} \\a=0.75hours$

6 0

3 years ago

Can someone please explain this to me I’m so confused and I have a quiz on this tomorrow

Ludmilka [50]

                               x^2 = 16/100
We must solve for x by taking the square root of both sides.
But imagine x^2 = 9. x = 3 is a solution because 3^2 = 9. But x = -3 is also a solution because (-3)^2 = 9. So we need to add the plus and minus sign to account for all of our solutions.
                     √x^2 = √(16/100)
We square root both sides to remove the exponent 2 on x. Then
                         x = ±√(16/100)
Then we have to use a Property of Radicals which is √(x/y) = √(x) / √(y).
Then the square root of 16 is 4 and the square root of 100 is 10. 4/10 is 2/5 simplified.

3 0

3 years ago

A large spherical structure has a 37.5-foot radius. The sphere is covered with panels. If each panel has an area of about 49 ft2

Citrus2011 [14]

Answer:

Option (1)

Step-by-step explanation:

Radius of the spherical structure = 37.5 feet

Surface area of each panel = 49 square feet

Sphere is covered with panels.

Therefore, area of the panels needed = $\frac{\text{Total surface area of the sphere}}{\text{Area of one panel}}$