Log16 4 = 2
log base 16 then the number four then set that equal to 2
Answer:
t = 4 seconds
Step-by-step explanation:
The height of the projectile after it is launched is given by the function :

t is time in seconds
We need to find after how many seconds will the projectile land back on the ground. When it land, h(t)=0
So,

The above is a quadratic equation. It can be solved by the formula as follows :

Here, a = -16, b = 32 and c = 128

Neglecting negative value, the projectile will land after 4 seconds.
Answer:
508.68 or 508.7
Step-by-step explanation:
V=1/3(3.14)(9)^2(6)
(3.14)(81) x 6
(3.14)(486)
1/3(1526)
(divide by 3)= 508.68
From here, just make it inverse:
