The answer to your question is x = -3
We have the <span> Trigonometric Identities : </span>secx = 1/cosx; (sinx)^2 + (cosx)^2 = 1;
Then, 1 / (1-secx) = 1 / ( 1 - 1/cosx) = 1 / [(cosx - 1)/cosx] = cosx /
(cosx - 1 ) ;
Similar, 1 / (1+secx) = cosx / (1 + cosx) ;
cosx / (cosx - 1) + cosx / (1 + cosx) = [cosx(1 + cosx) + cosx (cosx - 1)] / [ (cosx - 1)(cox + 1)] =[cosx( 1 + cosx + cosx - 1 )] / [ (cosx - 1)(cox + 1)] = 2(cosx)^2 / [(cosx)^2 - (sinx)^2] = <span> 2(cosx)^2 / (-1) = - 2(cosx)^2;
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For #7 I think it would be that the two triangles have the same measurements. Because angle E is 67 and angle G is 53.
Answer:

Step-by-step explanation:
In a direct proportion,
Pressure = constant × temperature
p = kT
We can use the initial conditions to find the value of k, and then calculate the pressure at the new temperature.
1. Determine the value of k
Data:
p₁ = 6 lb·in⁻²
T₁ = 440 K
Calculation:

2.Calculate the new pressure
