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s344n2d4d5 [400]
2 years ago
10

What is the value of the digit 2 in the number 425,611?

Mathematics
2 answers:
maw [93]2 years ago
7 0

Answer:

20,000 or 10,000

Step-by-step explanation:

The 2 is in the ten thousandth place, but the value is 20,000

mixer [17]2 years ago
5 0
The answer is 20,000
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During a fundraiser, students in Math Club make a $0.50 profit for every candy bar they sell. Let n represent the number of cand
enot [183]

Answer:

$5

Step-by-step explanation:

If every candy bar is $0.50 and they sell 10 just do

0.50 x 10 = 5

3 0
2 years ago
What is the surface area of the triangular prism? A. 13 in.2 B. 36 in.2 C. 78 in.2 D. 84 in.2
NISA [10]
Answer :36in2


example:
my math teacher told me
4 0
3 years ago
Find the value of x .. assume that segments that appear to be tangent are tangent .
Rus_ich [418]

Answer:

sqrt(277) =x

x is approximately 16.64331698

Step-by-step explanation:

This is a right triangle since 14 is tangent to the circle and 9 is a radius

We can use the Pythagorean theorem to solve this problem

a^2 +b^2 =c^2

9^2+14^2 =x^2

81+196 = x^2

277 = x^2

Taking the square root of each side

sqrt(277) = sqrt(x^2)

sqrt(277) =x

6 0
2 years ago
BRAINLIST HELP ASAPPPP PLEASEEEE DEW IN 5 MINNN
olga55 [171]

Answer:

(x+10)+(×+50)=180(exterior co- interior angel

2x+60=180

2×=180-60

×=120/2

×=60

(6x+3)=(7x-12)(corresponding angle )

3+12=7×-6×

x=15

4x-2=3x-19(vertically opposite angle)

4x-3×=-19+2

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4 0
2 years ago
Each of three coins has two sides, heads and tails. Represent the heads or tails status of each coin by a logical variable (A fo
jeka94

Answer:

(a) F(A, B, C) = AB'C' + A'BC' + A'B'C

(b) F(A, B, C) = (A' + B' + C')(A' + B + C)(A + B' + C)(A + B + C')(A + B + C)

Step-by-step explanation:

(a) If F(A, B, C) = 1 iff exactly one of the coins is heads, then either

A is heads and the others are tails (AB'C')

B is heads and the others are tails (A'BC')

C is heads and the others are tails (A'B'C)

Hence, as a minterm expansion,

F(A, B, C) = AB'C' + A'BC' + A'B'C

(b) To get the corresponding maxterm expansion, we convert to binary.

F(A, B, C) = \sum (100, 010, 001) = \sum(4,2,1)

The maxterm is the product of the complements.

F(A, B, C) = \prod (0, 3, 5, 6, 7) = \prod(000, 011, 101, 110, 111)

Expanding,

F(A, B, C) = (A' + B' + C')(A' + B + C)(A + B' + C)(A + B + C')(A + B + C)

3 0
3 years ago
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