Which proportion satisfies the geometric mean (altitude) theorem for the triangle? startfraction 2 over h endfraction = startfra
1 answer:
The proportion that satisfies the geometric mean (altitude) theorem for the triangle is 2/h = h/3
<h3>Triangular altitutude theorem</h3>According to the theorem, the ratio similar sides of a right triangle are equal. From the given diagram, we are to determine the proportion satisfies the geometric mean (altitude) theorem for the triangle.
Taking the ratio of the base to the height, we will have:
MK/KL = KL/KN
Substitute the measure of the sides
2/h = h/3
Hence the proportion that satisfies the geometric mean (altitude) theorem for the triangle is 2/h = h/3
Learn more on mean altitude theorem here; brainly.com/question/10216660
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Answer:
Step-by-step explanation:
Given that there is a function of x,
Let us find first and second derivative for f(x)
When f'(x) =0 we have tanx = 1 and hence
a) f'(x) >0 for I and III quadrant
Hence increasing in
and decreasing in
Hence f has a maxima at x = pi/4 and minima at x = 3pi/4
b) Maximum value =
Minimum value =
c)
f"(x) =0 gives tanx =-1
are points of inflection.
concave up in (3pi/4,7pi/4)
and concave down in (0,3pi/4)U(7pi/4,2pi)