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irina [24]
2 years ago
15

Mike understands the formula for temperature conversion, but is having difficulty imagining what various temperatures feel like.

which of these would be a good example to tell mike what 37°c feels like? a. room temperature b. a hot pan c. body temperature d. a chilly autumn evening
Physics
1 answer:
Alisiya [41]2 years ago
3 0

A good example that will help to to tell mike what 37°c feels like is body temperature.

<h3>What is room temprrature?</h3>

The average room temperature is typically around 20°C, or 68 degrees Fahrenheit.

<h3>What is body temperature?</h3>

The average body temperature is 98.6 Fahrenheit or 37 degrees Celsius.

Thus, a good example that will help to to tell mike what 37°c feels like is body temperature.

Learn more about body temperature here: brainly.com/question/5295345

#SPJ4

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Long Jump: inital center of mass height of 1.08 m, final center of mass height of 0.42 m, projection velocity of 8.7 m/s, projec
sammy [17]

Answer:

1) The maximum jump height is reached at A. 0.337s

2) The maximum center of mass height off of the ground is B. 1.64m

3) The time of flight is C. 0.834s

4) The distance of jump is B. 7.49m

Explanation:

First of all we need to decompose velocity in its rectangular components, so

v_{xi}=8.7m/s(cos 22.3\°)=8.05m/s= constant\\v_{yi}=8.7m/s(sin 22.3\°)=3.3m/s

1) We use, v_{fy}=v_{iy}-gt, as we clear it for t and using the fact that v_{fy}=0 at max height, we obtain t=\frac{v_{iy}}{g} =\frac{3.3m/s}{9,8m/s^{2}} =0.337s

2) We can use the formula y_{max}=y_{i}+v_{iy}t-\frac{gt^{2}}{2} for t=0.337s, so

y_{max}=1.08m+(3.3m/s)(0.337s)-\frac{(9.8m/s^{2})(0.337)^{2}}{2}=1.64m

3) We can use the formula y_{f}=y_{i}+v_{iy}t-\frac{gt^{2}}{2}, to find total time of fligth, so 0.42=1.08+3.3t-\frac{(9.8)t^{2}}{2}\\0=-4.9t^{2}+3.3t+0.66, as it is a second-grade polynomial, we find that its positive root is t=0.834s

4) Finally, we use x=v_{x}t=8.05m/s(0.834s)=6.71m, as it has an additional displacement of 0.77m due the leg extension we obtain,

x=6.71m+0.77m=7.48m, aprox x=7.49m

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When you stand on tiptoes on a bathroom scale, there is an increase in
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Answer:

B) Pressure on the scale, not registered as weight.

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This is because energy (derived from weight) becomes compiled on the tips of your toes, and therefore does not increase your weight, but simply the pressure at a smaller point

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6 0
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\small\bf \: thus \: time \: taken \: by \: sound \: to \: hit \: the \: cilff \: and \: return =  \frac{2x}{v}  = 1

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