Answer:
<em>1,378.9ms²</em>
Explanation:
Given the following
Distance S = 70.6m
Time t = 0.32secs
Initial velocity = 0m/s
Required
Acceleration
Using the equation of motion
S = ut+1/2at²
Substitute
70.6 = 0+1/2a(0.32)²
70.6 = 0.0512a
a = 70.6/0.0512
a = 1,378.9
<em>Hence the acceleration is 1,378.9ms²</em>
The correct answer would be 1.375 < t < 3 i hope this helps anyone
Answer:The net force on the block is zero.
Explanation:
Given
Block is being pulled upward along an inclined surface at a constant speed
As speed is constant and moved in a straight line along the plane therefore its velocity is also constant .
and change in velocity is equal to acceleration therefore acceleration is zero here i.e. net force is zero acting on the body.
we know that center of mass is given as
r = (m₁ 
+ m₂ 
)/(m₁ + m₂)
taking derivative both side relative to "t"
dr/dt = (m₁ d/dt + m₂ d/dt)/(m₁ + m₂)
v = (m₁ 
+ m₂ 
)/(m₁ + m₂)
taking derivative again relative to "t" both side
dv/dt = (m₁ d/dt + m₂ d/dt)/(m₁ + m₂)
a= (m₁ 
+ m₂ 
)/(m₁ + m₂)
